Well?

Well?

What field are we working over?
We could try [math]\mathbb{Z}_{26}[/math].

Just solve for x retard.

x-7=19+x
2x=12
x=6

what on earth does the subscript mean? Integers starting from 26? integers of 26 dimensions? the integer 26?

modulo 26

-7 = 19 (or 0 = 26) which is incorrect. so theres no solution.

1/10 thread

lol

You realise that it matters what field we're working in right? Especially here since [math]x[/math] cancels we end up with [math]-7 = 19[/math] which is nonsense over [math]\mathbb{R}[/math].
Furthermore, if we're working not working in an abelian group, then the cancellation law doesn't necessarily hold.

You may have seen it as [math]\mathbb{Z}/ 26 \mathbb{Z}[/math] instead.

>tfw still dont know what your talking about
what subject of math is this?

Pre-university for some. Try searching up modular arithmetic.
For example, when you tell the time you're working in mod 12 or mod 24 (depending on if you're using a 12 hour or 24 hour clock).
If not, then you will definitely see it in first term in an intro to abstract algebra course.

thanks bb

euclidian division. it really is easy to understand.
In Z/nZ, you consider two integers are equal if their remainders (when divided by n) are the same.

For instance in Z/3Z, you have 0=3=6=9=...
1=4=7=...=...
2=5=8=...

doesn't this have no solutions?

see

...

...

Yes, it has no solutions over [math]\mathbb{R}[/math].

Z_26 would just make it 0

and?

Make what 0? [math]x[/math]?
If yes then it doesn't matter what [math]x[/math] is because they cancel. We need the equation to make sense, and [math]\mathbb{Z}_{26}[/math] is one of the many fields in which it makes sense in.

I'm aware, I was just stating the result

Then you've missed a lot.
Over a field [math]\mathbb{F}[/math] in which the equation makes sense the solution set is [math]x \in \mathbb{F}[/math].

>integers of 26 dimensions
top kek, thank you

I cant tell if youre being serious or just an actual complete retard

Bloody hell you're right; I went full retard, my bad

"integers of 26 dimensions" would make more sense if it was [math]\mathbb{Z}^{26}[/math].
Maybe you misread the subscript as a superscript?

x-7=iq+x
-7=iq
q=-7/i

x-7=19+x
x=x+26
x-13=x+13
|x|=13
sqrt(x^2)=sqrt(13^2)
sqrt(xx)=sqrt(13*13)
xx=13*sqrt(xx)
x=13.
This is 8th grade algebra, guys.

See

...

second one has to equal 0.

When you add terms such as [math]x^2[/math] you're also adding extra solutions so you have to be careful to check that those extra solutions actually satisfy the original equation.
It's like squaring an equation and finding that some solutions are actually invalid.
For example, over [math]\mathbb{R}[/math]:
[eqn]\begin{align}x = 1\\ x^2 = 1 &\text{, by squaring}\\ x^2 - 1 = 0\\ (x-1)(x+1) = 0\\
\implies x = -1 \text{ or } x = 1\end{align}[/eqn]

But clearly [math]x=-1[/math] does not satisfy the original equation.

T h i s

Did they solve it in the anime?

One of the students calls the teacher out and says it has no solutions IIRC

x-7=19+x
x=19+6x
-5+x=19
x=24

no x

x's cancel out

-7 = 19

You can't just assume that, see:

6=32

???

24-7=17
19+24=43
>try again

>not knowing basic uni maths
>posting on Veeky Forums

just get out

45

x-7=19+x

The only way you can get 19 from minus 7 is by having x be 26, so you have x and 19=45

Isn't that the non common core way of solving it? I think everybody in this thread is using common core formulas

Two parallel lines can never intersect.
No solution.

can't solve, not enough information

>mfw

>oh wow so le complicated XD

topologists are all just arrogant tossers hiding behind their big words.

...

Sorry you can't grasp simple homology theory my man.

you're right in that the concept is almost obvious when you understand the hypothesis statement, but the nomenclature is also essential to remain precise.

It doesn't have a solution.