Hey, it's been a while Veeky Forums. While I'm updating my computer, let's play a game.
A while back I downloaded a quarter million clues from a Jeopardy archive. Give a category and difficulty
category | approx number of questions science 3964 economics 2352 physics 1048 chemistry 424 biology 471 astronomy 599 math 401 engineering 281 geology 256 inventions 1537 psychology 521
I have math puzzles/problems, but they aren't jeopardy questions
Brayden Nguyen
post a few top difficulty math ones
Liam Anderson
Or did you mean the puzzles?
Christopher Peterson
What is the additive identity
Leo Sullivan
>.> correct. category, difficulty?
Noah Johnson
Science 800 idk
Adrian Gonzalez
...
Alexander Howard
What is plastic?
Josiah Reyes
correct, category?
Connor Carter
Math
Hardest (idk the number)
Jason Reed
...
Eli Hill
What is calculus
Jaxson Bailey
correct, category?
Jayden Sanders
Chemistry hardest
Colton Turner
...
Parker Sanders
What is chaos?
Robert Allen
Correct, category?
Alexander Wright
Not guy who asked question but what is chaos.
Noah Turner
Engineering 600
Wyatt Rodriguez
Math second hardest.
Brody Jackson
...
Henry Wood
Who was Eiffel?
Juan Clark
Correct
Daniel Brooks
google
Kayden Wright
Correct, category?
Easton Jenkins
Biology 200
John Nelson
...
Brandon Hughes
What is a Dove?
If correct: Astronomy 600
Christopher Reyes
...
Cameron Jenkins
What is squab
Luis Campbell
Correct, sorry for the wait
Bentley Taylor
What is solar wind?
Justin Cooper
Correct, category?
Sebastian Rivera
Chemistry 2nd hardest
Jace Sullivan
...
Wyatt Edwards
Tungsten
Caleb Morales
Correct, category?
Anthony Russell
math nigga, hard.
Cooper Gonzalez
didn't know they call wolfram tungsten, thx
Michael Roberts
...
Nathaniel Cox
What is numbers
Jonathan Martinez
What is number?
Jaxon Bell
what is multiply?
More math plx
Easton Lee
tau/2
Julian Ramirez
correct
Henry Evans
forgot my image, sorry for the wait
Wyatt Harris
(four and twenty) / three
Carter Baker
correct, category?
John Nelson
math
Liam Anderson
During a baseball game in Mudville, Case was Mudville's lead-off batter. There were no substitutions or changes in the batting order of the nine Mudville men throughout the nine-inning game. It tured out that Casey came to bat in every inning. What is the least number of runs Mudville could have scored?
Justin Phillips
user, the one above you asked for a math question, not a sport one
Asher Torres
13?
Grayson Hall
nope, there's a smaller answer. I also require a short proof for these. Here have another: With a 7-minute hourglass and an 11-minute hourglass, what is the quickest way to time the boiling of an egg for 15 minutes?
Hudson Jackson
i'm still working on the baseball one but for the hourglass one you need to wait 7+4+11=22 minutes?
Charles Watson
boil the egg for 15 minutes
Ian Stewart
>7+4+11=22 minutes? That's a solution, but not the optimal one. Also show how!
Ryder Peterson
set the timer to 7,5 twice
9 runs? 3 runs for every third inning?
Aaron Jackson
How do you set an 11 minute hourglass to 7.5? > 9 runs? nope. fewer
Lucas Harris
you eye ball it
Juan Perez
Flip the 11-minute and 7-minute at the same time. When the seven-minute is finished, flip the eleven-minute and boil the egg. When the 11-minute is finished, flip it. When it is finished, 4+11=15 minutes will have passed, and the egg is done.
Thomas Adams
Wait, no: you can do it in 15 minutes, the minimum. Boil the egg and set both hourglasses. When the seven is finished, flip the eleven, and when that is finished you are done. No solution can be faster because it would take less time than it takes the egg to boil.
Math, hardest.
Isaac Morris
Start both hourglasses at the same time. When the 7 minute one runs out, you'll have 4 minutes left in the 11 minute one. Start your egg. When the 11 minute one runs out, turn it over. When the 11 minute one is out, the egg has been cooking for 15 minutes.
William Hughes
That's 14 min. Pretty sure And by math do you want puzzles or more jeopardy questions?
Austin Davis
fuck I never thought to delay starting the egg
Christopher Bennett
Set both timers and boil the egg. After the 7 runs out reset it. After the 11 runs out flip the 7. When the 7 runs out 15 minutes should have passed. Pretty sure that's the optimal.
Justin Ward
It's fifteen. And, math puzzles sound nice.
Robert Richardson
MAKE WITH THE JEOPARDY-STYLE MATH QUESTIONS OP.
Ayden Edwards
Correct. Give me a min for more clues
Adrian Rodriguez
>Here have another: >With a 7-minute hourglass and an 11-minute hourglass, what is the quickest way to time the boiling of an egg for 15 minutes?
What's a general form for solving these types of questions?
Matthew Myers
I don't think there is one. That's the beauty. Here's another one for whatever algo you want to develope: How do you measure 9 minutes with a 4min and 7min hourglass?
Carter Richardson
and for the puzzle, how about a classic: Three missionaries and three cannibals must cross a river using a canoe, which can only carry two people. But if there are ever more cannibals than missionaries on either shore, the cannibals will overpower the poor missionaries and eat them. There's a strong current so the boat cannot be sent across the river without any people rowing.
Luke Collins
Start 4 and 7. When 4 is out flip both. When 7 is out flip 4 Let 4 run out.
Ayden Ward
Set both timers. When the 4 finishes reset it (4 mins). When the 7 finishes (7 mins) flip the 7. When the 4 finishes (8 mins) flip the 7 again and wait till the minute's worth if sand runs out.
Juan Lee
youre getting nice digits this evening
and the jeopardy seems really weird, is their something apart from a protractor that measures angles?
Elijah Mitchell
Geology for 500 points
Ayden Gray
Sextant? The etymology seems wrong.
Jeremiah Taylor
I'm going to post "octant" before checking.
What is an octant?
MAKE WITH ANOTHER MATH QUESTION. ENGAGE WITH YOUR THREAD.
Zachary Gutierrez
Octant nigs
Grayson Carter
I'll agree that's right for 1/8.th. Never knew it was a measuring device
Aaron Ross
correct
Brandon Ross
Altitude. More math or linguistics
Blake Jones
In diagram form Left side | Right Side | Boat direction mmmccc | | -> mmcc | mc | mmm | ccc | mc | mmcc | cc | mmmc | c | mmmcc | | mmmccc |
Easton Morales
Also did anyone get the 9 minute candle right?
Jack Phillips
What is
Matthew Garcia
22 is absolutely the optimal solution. The only periods of time when a timer can have finished before 22 minutes are minute 0, 7, 11, 14, 18, 21, and 22. Only 22-7 allows you to measure out 15 minutes.
The method to cook the egg is to run the eleven minute timer twice and the seven minute timer once. Start boiling the egg after the seven minute timer finishes.
Jacob Bennett
It wasn't asked, but burn one candle from one end and the other candle from both ends. When the second candle finishes, burn the other end of the first candle.
Kayden Baker
See
Jordan Morales
I meant the hourglass but fucked up.
Carson James
oh
candle problems are different from hourglass problems
you can understand my confusion
Blake Sanchez
Seems valid
Colton Morgan
>> 9 runs? >nope. fewer That doesn't seem possible. If the first batter pitches in every inning it means you need 9*8+1 or 73 batters at least. Each inning 3 of these batters will get an out, and contribute nothing to the run count, so we can subtract off another 3*9=27. Leaving us with 56 batters. Essentially every 4 batters, a run is scored, which should make the minimum 14, yet I already found a solution for 13 so that can't be right. If you want to get it so that there's less than a run per inning you'd have to arrange it in a very clever way. This kinda reminds me of the 8 queens puzzle.
Jace Peterson
Seems they don't need a run in the last inning for Casey to bat if he bats first.
Luis Davis
So apparently this was a real game. The solution is 0 runs. I'll type it out later because theres lots of color.
Thisll prob be it for today. My comp is back to full power
Jace Stewart
Please do I'm really curious about this.
Aiden Fisher
Actually I just looked it up because I couldn't wait. I knew I was missing some sneaky baseball rule. It turns out if you're at bat while another player gets out stealing a base you will get first at bat next inning. It was the extra piece I needed to actually solve this. Feel free to type out your colorful solution though.
Daniel Evans
Biology, 304
Christopher Carter
Can you query this backwards. Can I ask a question and you give an asinine jeopardy answer.
Lincoln Nguyen
That was indeed an amusing problem concerning Casey and the Mudville nine--amusing, that is, to all save lovers of Mudville. For on the unfortunate day described in your problem, Mudville scored not a single run. This is what happened:
In the first inning, Casey and two of his confreres reached base, but batters four through six struck, flied, or otherwise made out. No runs.
In the second inning, batters seven and eight struck out, let us say, but the Mudville pitcher, to the surprise of all, reached base on a bobbled infield roller. Casey came up to bat, frowning mightily. With the count two and two, the perfidious rival pitcher, ignoring the best interests of poetry, baseball mythology and Mudville, whirled toward first and picked off his opposite number, who, dreaming of Cooperstown and the Hall of Fame, had strolled too far from the bag. THe crowd sighed, Casey glowered, and the inning was over: no runs.
Now as you know, if an inning ends with a pick-off play at any base, the batter who was in the box at the time becomes the first batter next inning. So it was with Casey; once again Mudville loaded the bases; but once again three outs were made with no runs scoring, so that the inning ended with batter si making the last out.
Life may be linear but fate is cyclic: innings four, six, and eight followed precisely the same pattern as inning two (though you may be sure that after his second miscue in the fourth, the Mudville pitcher was lifted and his relief was responsible for only the flood of runs the opponents scored, but for similar cloud-gazing base-paths). And of course, Case led off the fifth, seventh, and ninth innings as he had the third--and again, Mudville would load the bases, but could not deliver (if I remember correctly, the gentlemen responsible for this orgy of weak hitting were Cooney, Burrows, Blake and Flynn). Grand total for Mudville: a goose egg.
Sorry I was unaware of that trick too. Becomes a baseball question.
Ethan Edwards
To make up for it:
Each end of a 10-foot length of rope is tied securely to a man's ankles. Without cutting or untying the rope, is it possible to remove his trousers, turn them inside out on the rope, and put them back on correctly?
Most of these puzzles were taken from Martin Gardner's Colossal Book of Short Puzzles and Problems.
Cameron Watson
Yes, take one leg of the trousers and move them up through the other leg of the trousers. If you pull all the way through the pants will be turned inside out and can then be worn.