9/10 Facebook users can't even

9/10 Facebook users can't even

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wolframalpha.com/input/?i=\int_(-1)^( 1) sin(x +arg(-1) )dx
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the main "joke" of these cancer riddles is using undefined notation like two overlapping horseshoes in one place and a single horseshoe in another. This is perfectly doable with the four pictures interpreted as variables, so you failed miserably, OP.

...

Ridiculous

...

The bottles = 10 each.
Burgers = 5
Booze = 2.

* (Tan-1*5/x)
S (-------------) * dx
* (x*ln(2)^10)

This is what I got too. But it's an indefinite integral, so I don't know how we're expected to come up with a final value.

but we haf noot defined nick cage

You don't really seem to get what I'm saying.

lrn 2 LaTeX

>S (-------------)
Get the fuck out

\begin{document}
\frac{Tan-1*\big(5\div{x}){x*\ln{2}\^{10}}}

\end{document}

Testing

>[math] \displaystyle \int \frac{\tan^{-1}\frac{}{}}{\ln()^}d [/math]

EPIC FAIL

it's not asking for a value it's just asking for the answer

ez

>differential of a constant

wat

Oh wait I'm retarded. It's not too bad then, it just doesn't have any limits. No biggie, just don't forget that C

>it just doesn't have any limits

It's called an anti derivative, freshie.

pls no bully

That's the way, shit on all these latex fags

That should all be multiplied by [math]\frac{1}{\ln(2)^{10}}[/math].

F U C K L A T E X

what is Li?

Li_2 is the second order polylogarithm function

that's pretty lit desu

I need some 4x4 mm stickers showing Nic Cage's face so I can use them as variable names on my next exam.

How about this one? Bit simpler, going to see which of my normiebook friends can figure it out. Most of them got their a levels so I hope at least some can.

what's there to solve here? the answer is clearly burger

You're supposed to find out what number burger corresponds to.

Go on.
Hint: [math]\arg(a \cdot e^{i\phi}) = \phi[/math]

wolframalpha.com/input/?i=\int_(-1)^( 1) sin(x +arg(-1) )dx

[math]\int_{-1}^1\sin(x + \pi)dx = - \int_{-1}^1\sin(x)dx = \int_{0}^{-1}\sin(x)dx - \int_0^1\sin(x)dx = 0[/math]