/wrs/ is a ghost town, I don't know how much better than there here will be...
Help me out guys?
How do I simplify in 3D?
/wrs/ is a ghost town, I don't know how much better than there here will be
Josiah Lopez
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Eli Scott
how wrong am I?
Brandon Rogers
Instead of isolating E=1 on the right side, rearrange the literals so A=1 on the right side. That will make things simpler.
Christopher Scott
why kmap for 5 variables
Oliver Price
you can do better
Landon Ortiz
>>construct a 0-15 up/down counter utilizing type D JK master-slave flip flops
The E enables the counter to count downwards
Hudson Long
Oh I see. Does this mean I was wrong?
Eli Bennett
E'AB' + ABC' + ACD' + EAD + A'B'C'D'E + A'BCDE'
Caleb Bennett
Better yet, capture a block of 16 and exclude the two holes.
David Rivera
Which would reduce to just five minterms
Samuel Brooks
Also does this make the following the simplest expression?
D0 = E'A'BCD + E'AB' + EA'B'C'D' + EAD + ABC' + ACD'
Dylan Perry
I'm not sure what you mean by this...
Christian Gray
Something like
(A and not BCD and not B'C'D') or A'BCD or A'B'C'D')
Daniel Martinez
This?
D0 = E'A'BCD + EA'B'C'D' + A(EAB'C'D'+E'ABCD)'
Jordan Brown
Which further simplifies to (A and (B xor C xor D)) or (A' and (B xor C xor D))
Which simplifies to
B xor C xor D
I think?
Tyler James
BCD + B'C'D' + (B xor C xor D)
Evan Collins
What is this?
John Smith
Scratch that.
Actually, xor(A,B,C) or xnor(A,B,C), which isn't the same as my previous answer.
The output is 1 if A=B=C or if one of them differs from the other two.
Nathaniel Peterson
Actually, xor(B,C,D) or xnor(B,C,D), which isn't the same as my previous answer.
The output is 1 if B=C=D or if one of them differs from the other two.
Xavier Scott
It is a 3D Karnaugh Map. It is used to simplify Boolean expressions in order to build a circuit as efficiently as possible (at least in this context)
I need to know how to build a 0-15 (16) up/down counter from type D JK master-slave flip flops.
Being a 0-15 counter means I need 4 bits, or 4 flip flops (15 = 1111 in binary). That means 4 variables.
The fact that it needs to go either up or down means I need an extra input to allow for this condition, namely E, which means I now have 5 variables.
I'm not very good with Karnaugh Maps nor Boolean algebra.....
Sebastian Baker
>/wrs/ is a ghost town,
So what?
Fuck off, this isn't the place to post your homework.
/mlp/ being inactive, for an example, won't allow you to post pony porn on this board.
Anthony Bennett
Thanks user. However I'm rapidly realizing my grasp on the rules of Boolean Algebra needs some serious tightening....
I was having a hard time understanding the consensus theorem just now, for Pete's sake......
Angel Sanchez
thanks for being friendly
I just needed some help understanding some concepts. Not homework.