How do I do this?
E^x=(x^2)-2
James Myers
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Alexander Baker
F2 -> Solve
Elijah Richardson
That doesn't help very much
David Wilson
There is no closed form solution, I believe x would have to be transcendental.
Also, here's the answer if you need it:
wolframalpha.com
Carter Jenkins
Couldnt you just take ln on both sides to get e off?
Jayden Garcia
Jordan Green
that image makes absolutely no sense to me
Ryan White
f(x) = e^x - x^2 + 2
f(-1) = 1.36...
f(-2) = -1.86...
f(0) = 3
f(1) = 3.78...
f(2) = 5.38...
Well it's between -1 and -2.
e^x = x^2 - 2
1 + x + x^2 /2 + x^3 /3! + ... = x^2 - 2
3 + x - x^2 /2 + x^3 /3! + ... = 0
aaand I can't go anywhere from here
Caleb Garcia
use newtons method
make a guess for about where they'll be equal.
say x_0 = -1.5.
let f(x) = e^x - x^2 + 2 = 0
the derivative will be
f'(x) = e^x - 2x = 0
now we can get a better approximation by computing:
x_1 = -1.5 - [f(-1.5)/f'(-1.5)]
this new better approximation, x_1, is about −1.5181297346 if i calculate it right
you can then repeat this, using x_1 instead of x_0, to find x_2, an even better estimation.
Hunter Morgan
thank you
Brayden Sanchez
peace of cake
[math]\frac{d}{dx}e^{x}=\frac{d}{dx}(x^{2}-2)[/math]
[math]\frac{d}{dx}e^{x}=\frac{d}{dx}2x[/math]
[math]e^{x}=2[/math]
[math]x=ln\;2[/math]
Eli Gomez
I am going to give you 5 minutes for you to tell me why what you just wrote is completely fucking wrong.
If you see nothing wrong or can't find it then please go back to /g/. Those guys are closer to your level.
Oliver Bennett
oh right, i misspelled piece
Levi Price
Back to /g/.
Oliver Baker
x is a constant, not an variable.
so if you differentiate e^x=(x^2)-2 where x is a constant, you get 0 = 0, which is not useful.
checkmate :)
Benjamin Morris
i feel like this involves the W "function"
Wyatt Ward
You guys are idiots.
Ethan Carter
why?
William Mitchell
>d/dx e^x = e^x
Caleb Hall
WOW YOU'RE RIGHT, THAT'S WHAT'S WRONG ABOUT THIS COMPUTATION!
Hudson Gonzalez
How to solve 2x = x^2 (by your logic)
[math]\frac{d}{dx}2x= \frac{d}{dx}x^2[/math]
[math]\frac{d}{dx}2= \frac{d}{dx}2x[/math]
[math]0= 2[/math]
Then, because contradiction implies everything, x takes on every possible value.
Dylan Gomez
stop being rude I just started taking calc 1 at community college
I just wanted to fit in
Evan Ramirez
get out
Gabriel Sanchez
no
Levi Rivera
you learned power rule this quickly in the semester?
Daniel Perry
What the fuck is that pic, comrade?
Joseph Jenkins
>started with simple differentiation
>went over rules, including power rule in first weeks
should we have taken longer or something?