Why would they fall towards each other at the same rate?

Why would they fall towards each other at the same rate?

This makes no sense.

[math] F= ma = mg \implies a = g [/math] Acceleration due to gravity is independent of mass.

>not using [math] F_g=G\frac{m_1m_2}{r^2}[/math]

Your math code isn't showing up but if F = ma, m = mass so wouldn't that increase?

Also why would gravity be different on other planetary bodies but the same on earth? Makes no sense

Inertia, that's why.
Little energy needed to move a small object, but also smaller force.
A big object experiences much more force, but at the same time much more energy is needed to move it.

Maybe not the most accurate explanation, but it will do the job.

BTW, mars is smaller than earth

They wouldn't. While the feather would simply fall towards earth, earth and mars would both fall towards their collective center of mass. Since [math]\mathrm{\it{both}} [/math] earth and mars are accelerating together at the same rate as the feather towards earth, from earth's point of view, mars appears to be falling faster, despite it moving at the same speed of the feather from the point of view of an inertial reference frame.

>While the feather would simply fall towards earth, earth and mars would both fall towards their collective center of mass.

Actually that's true in both cases, the Earth does "fall towards" the feather as well as vice versa.

So why would a feather fall at the same time as ?

you're right it doesn't, it's because flat earth exists

Unless they were in a vacuum chamber, they wouldn't. Air resistance would play a huge part in slowing the feather.

Yeah, yeah, yeah.
You're very edgy, and very special.

But not as fast.

Also fuck you, Mars is only about as big as the moon not bigger than the earth you cunt.

They wouldn't both collide at the same time.
The feather gets an equal acceleration towards the center of mass to the one Mars gets but the earths would have different accelerations becausw the feather has a weaker pull than Mars.

>if F =ma, m = mass so wouldn't that increase ?

Not him, just passing by but considering the only force applied here is the weight, F = mg. Newton said in his 2nd law that the sum of every forces is equal to m.a . So F = mg = ma. Leading to a = mg/m = g so acceleration is not dependant from mass.

This is the worst board here
Worse than /pol/ or /tv/ or /x/ or /g/ or /v/
Let that sink in

what kind of sink are we falling into here?

>(2.95 MB, 4000x4000)
neither does this

So the surface gravity on the Moon and on the Earth are the same? You didn't quite think this through.

To know the rate at wich they move, you need to describe their distance relative to one another.
Distance is an symmetric notion.
that is why they fall towards eachother at the same rate.

I actually enjoy watching when they use scifi babble now.

Falling is means moving towards earth, the force may be different, however the acceleration (The fucking thing that is falling) Is the same.

Devide that by m, the mass of the object, and you have the accceleration.

>[math] \text { Curvature } = [ \text { inches } \text { mi } ^{-1} ] \times [ \text { mi } ^{ 2 } ] [/math] Kek

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Golly, user - you sure find the tough questions. Using Google to search on "lunar rover stowed" didn't turn up any results.