Professor asks us to find the derivative of 2^π

>professor asks us to find the derivative of 2^π
>Write 2π^π-1

>not writing [math]\pi\,2^{\pi\,-\,1}[/math]
Brainlet indeed.

>not writing ln(2)2^π
Brainlet indeed.

someone in my calc3 class asked my professor if they could simplify sqrt(4-cos^2x) to 2-cosx. The despair was audible in his response

>ln(2)
im confused, how can you substitute ln(2) for π2?

I'm new to this board pls don't hurt me I just like math.

it makes no sense and he is just kidding. But to get rid of exponents to make calculations easier you can take its logarithm, usually natural log, because of the log laws. A log raised to the power m in say ln(x)^m can be rewritten as mln(x). So if you have something like 2^x= 34 you can make the equation easier by taking ln of both sides to get xln(2)=ln(34) so x=ln(34)/ln(2)

and btw OP is kidding too because 2^pi is a constant and its derivative is 0 but he is treating pi as a variable, which is a mistake.

Makes sense

Actually understood all of the shit on this page I was assigned today, took me a few minutes, but when I finally understood everything my dick was rock fucking hard.

Did you check your answer by integrating?

It's 0 you dickheads

>professor asks us to find the derivative of 2^π
With respect to what? If its anything other than pi then its zero

pi is a constant not a variable you fucking dolt

:^) you're joking, right friendo?

there was one point in our calc 3 class where multiple people got confused with the homework since at one point it showed that cos^2(x) = cos(2x)/2 because the derivatives were equal
forgot exactly how the problem got to that but it had to do with integrating vector functions and having to have initial conditions

i wanted to kill myself right then and there, i think the professor felt the same

>d/dπ 2^π
ah yes
the limit as a constant approaches a constant

No I'm actually this low level math boy pls help

>2^pi is a constant
>pi is a constant
Have you LITERALLY checked every circle to prove this claim?

Are you underage?

prove it, big boy

my physical intuitions tell me all i need to know, son

>using proof by exhaustion for infinite cases

But pi is a constant you silly goose

>not realizing [math]\frac{\operatorname{d}2^\pi}{\operatorname{d}\pi} = 2^\pi \ln 2[/math]
Brainlet indeed.

>infinite sets

>not writing 0
fucking drop out

Not writing x+b

>infinitely many circles
that really rattles my physical intuitions

You can

What's the big deal?

There is only 1 circle and different scalers of that 1 circle.

>The derivative of a constant
Zero faggot.

would you say the product rule is your...specialty?

apex kek

You can define pi to be a variable you fucking tard.

>implying you can't define pi to be a variable
you're all retarded

>not defining 2 to be the variable and pi the constant

brainlet

kek

The derivative of 2(pi) is zero lol jajajajja

>Makes sense
I don't know if this thread is real or not

Plato pls.