Why doesn't this circuit work? What am I doing wrong here?

Illusionz
Illusionz

Why doesn't this circuit work? What am I doing wrong here?

Attached: faulty-circuit.jpg (8 KB, 478x478)

Raving_Cute
Raving_Cute

Attached: wr.png (16 KB, 672x205)

Crazy_Nice
Crazy_Nice

but that's not a short circuit

Booteefool
Booteefool

If you draw a circuit like that, then you may want to be studying a little bit more.

MPmaster
MPmaster

define work.
also, try using kirchhoff's laws to do analysis on the loops and junctions

viagrandad
viagrandad

I think it is, user

askme
askme

how?

iluvmen
iluvmen

You're short-circuiting that one resistor.

idontknow
idontknow

how is that a problem for the entire circuit?

Techpill
Techpill

Why doesn't this circuit work?

You're using a capacitor in a DC circuit.

What am I doing wrong here?

Literally everything.

Carnalpleasure
Carnalpleasure

I don't understand why it wouldn't still work, I'm at a loss here

Firespawn
Firespawn

That's precisely why it doesn't work. You don't understand some basics. Start over and follow the foundation logic.

CouchChiller
CouchChiller

you'se using MS paint

eGremlin
eGremlin

I can't see anything wrong with it.

That isn't how it works

BinaryMan
BinaryMan

And what? What if it's a ceramic disk capacitor? And why can't you use a cap in a DC Circuit, if you check the - and + correctly?

CodeBuns
CodeBuns

What's the load? Won't this just heat up and explode?

New_Cliche
New_Cliche

It blocks DC voltage.

Spazyfool
Spazyfool

and what? the circuit still works, the part with the capacitor is just not powered since the cap is filled

Stark_Naked
Stark_Naked

This has gone from noob to bait territory.

Need_TLC
Need_TLC

Reported, saged, hide, ip hacked, and I am coming for your family.

Methshot
Methshot

there will be a power loss

Methnerd
Methnerd

What should it even do? Define work as
said.

Firespawn
Firespawn

Why doesn't this circuit work?

What do you mean, "doesn't work" - what did you expect to see that you aren't seeing?

RumChicken
RumChicken

No, the cap will drain the battery in seconds. This is how the circuit should look like.

Attached: 111.png (4 KB, 550x198)

SniperGod
SniperGod

is this loss?

5mileys
5mileys

Fuck

massdebater
massdebater

Brainlet here, why isn't the fact that there's a resistor in parallel with a wire not a problem? Wouldn't no current flow through the resistor?

PackManBrainlure
PackManBrainlure

Not strictly a problem, just a resistor that would be ignored. But that still doesn't really answer OP's shitty vague question.

AwesomeTucker
AwesomeTucker

It blocks DC voltage.

Attached: 1511157026333.jpg (46 KB, 512x384)

BunnyJinx
BunnyJinx

the cap will drain the battery in seconds

Attached: 1506116542390-(1).jpg (374 KB, 2048x1365)

BlogWobbles
BlogWobbles

Define "work"
Right now you have current through the two loads in the bottom right

ZeroReborn
ZeroReborn

wait a second op...

Fried_Sushi
Fried_Sushi

force times distance

Need_TLC
Need_TLC

distance raptor/time raptor = velociraptor

Fuzzy_Logic
Fuzzy_Logic

you're right

Evilember
Evilember

I don't get it

happy_sad
happy_sad

I guess the joke is lost on you.

ZeroReborn
ZeroReborn

The impedance of a capacitor is [math]\frac{1}{i\omega c}[/math], for DC [math]\omega[/math] is 0 so the impedance is infinite and thus no DC can pass

Stupidasole
Stupidasole

Are you trolling or something?

It's just an RC circuit. It's not really going to DO anything without some kind of active element like a transistor or op-amp or something. Also, you have a resistor with both ends connected to the same node so it won't do anything because there is no voltage across it.

Attached: what.png (8 KB, 597x534)

Nojokur
Nojokur

using i instead of j for a circuit

Attached: 1429904286107.png (14 KB, 646x720)

Soft_member
Soft_member

It seems that you're at a loss of power

takes2long
takes2long

This is a great IQ test.
I'm gonna use it next time I interview someone.

TechHater
TechHater

this
all you guys didn't get it holy shit

farquit
farquit

So what field is this? Who studies this stuff? Electricians?

T.brainlet

haveahappyday
haveahappyday

/v/

takes2long
takes2long

Capacitors are short circuit for DC signals.

Playboyize
Playboyize

That's not entirely true - if it's discharged yes it's a short circuit but if it's fully charged it's an open circuit

Methnerd
Methnerd

That isn't how it works
It's common to say that when a component is bypassed with a wire, the component is shorted.

Firespawn
Firespawn

Electrical engineers
...with a mimetic behavior bend.

CouchChiller
CouchChiller

Specify what you mean by "doesn't work".

Regardless of your answer, that circuit in steady-state is essentially a single load, a purely linear resistor. The upper resistor is shorted and the capacitor does nothing, so you have two resistors in series and that's it.

Ignoramus
Ignoramus

all you guys didn't get it holy shit

"I showed a meme image that looked like something board relevant on a board that isn't drowning in that meme, and people thought it was relevant instead of a meme" T. user, 2018, University Press Department of Auto-Ethnographies.

Spazyfool
Spazyfool

Why are there two positives on the bottom

Dreamworx
Dreamworx

It's a capacitor.

haveahappyday
haveahappyday

Case closed.

New_Cliche
New_Cliche

j is for engineering plebs

Deadlyinx
Deadlyinx

effective circuit, we see that the circuit actually works

Attached: steady-state-behavior.jpg (47 KB, 987x478)

Emberfire
Emberfire

What's it supposed to do? I see a directional capacitor, a capacitor and three objects of unknown properties, possibly resistors.

Deadlyinx
Deadlyinx

you need to learn how to draw and read circuits, that IS a short circuit, it is a path of virtually no resistance between two points
study harder before posting your homework here

Evilember
Evilember

putting a capacitor in parallel with resistors does not charge the capacitor even a little?

I find that hard to believe

Firespawn
Firespawn

I check for secret doors

Flameblow
Flameblow

op said nothing about steady state.

Playboyize
Playboyize

And how is that circuit even supposed to work? What should it do?

Attached: 1521573820126.jpg (112 KB, 1018x1018)

askme
askme

I thought short circuits(non trivial) were paths from one end of the power source to the other without resistance

SomethingNew
SomethingNew

No the fuck it is not, it's for anyone who knows how to properly analyze circuits. Granted those are usually engineers.

cum2soon
cum2soon

Is this Pentium processor?

whereismyname
whereismyname

it does
his image only analyses the circuit for the steady state when the capacitor is already charged

Raving_Cute
Raving_Cute

Bypassing any kind of element in the circuit via 0 resistance wire (or for example copper wire in practice) is considered to be short circuiting.

JunkTop
JunkTop

R1 and R2 make a voltage divider. the capacitor is irrelevant because it's dc, and the other resistor is parallel with a short circuit.

Attached: faulty-circuit.png (24 KB, 478x478)

Garbage Can Lid
Garbage Can Lid

what the fuck? in which shithole country do you draw the voltage like a capacitance?

FastChef
FastChef

not OP but
Symbol most likely specifies a battery rather than simply any voltage source. I was told to use circles with + and - for sources that can be assumed to be infinite for the purposes of the circuit, like a wall outlet and the battery symbol ones for ones that are not, like batteries.

Booteefool
Booteefool

Hey since this is the Electronics for Retards thread can I replace this IF transformer with a differential amplifier?

IF cans are hard to find and expensive compared to a few decades ago and I hate winding my own transformers. I still want good isolation between the LO and IF. Diff amp is high impedance and it allows me to impedance match easily. Throw a buffer on the output and throw a 50 ohm resistor on the output. Easy 50 ohm output impedance.

Attached: if-amp.gif (7 KB, 543x419)

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