Barring actually purchasing a three-sided die, what's the best substitute for rolling a d3?

Barring actually purchasing a three-sided die, what's the best substitute for rolling a d3?

d2+1

d6
1 2 3 are as normal
4=1
5=2
6=3

A d6.
If you use one regularly, just colour in some of the spots to make the number obvious.

fucking plebs

>roll 1d100
>check to see if it's 01, 02, or 03
>otherwise reroll
>goto 10

Specially numbered d6s. I have several. Bought one for my dad for his birthday cause he plays a halfling rogue who uses a dagger.

1 or 2 = 1
3 or 4 = 2
5 or 6 = 3

This. The warhammer way. It has never come up as an issue or with any confusion in any games that I have played. It's gotten to a point when I know im rolling a d3, when a 2, 3, 4, 5, or 6 come up, i don't see those numbers. I see 1, 2, 2, 3, and 3 respectively.

hero

Either:

d4, reroll 4

d6 mod 3

>not using d2 for everything

>d2
>neglecting the edge

>Neglecting the atoms.

"roll" 2d2
head/head = 1
head/tail = 2
tail/tail = 3

wut? Just use n/2 rounded up. 1/2 = 0.5 rounded up to 1, 2/2 = 1, etc.

d2 gives an average result of 1.5
+1 makes it average 2.5
a d3 should be average 2
as people have said, a d6 is the best solution
if you wanted to use a coin, use 2d2, which will output a total of 2, 3, or 4. Then subtract 1 for outcomes 1, 2, or 3.

>Veeky Forums cannot into probability
head/head = 1/4 chance
head/tails = 1/2 chance
tails/tails = 1/4 chance

Compare to a d3:
1: 1/3 chance
2: 1/3 chance
3: 1/3 chance

These two things are not the same.

Roll d6, divide by 2, round up. How is this even in question?

Roll a d30 and divide by 10

Roll a d9 and dive by 3

d6

Roll a d51 and divide by 17 is probably the best method.

Roll a d12
1,2,3,4 = 1
5,6,7,8 = 2
9,10,11,12 = 3

OR

1,4,7,10 = 1
2,5,8,11 = 2
3,6,9,12 = 3

Harvey pls

I have a d6 with 2 sides marked •, 2 sides marked •• and 2 sides marked •••. I don't have this problem.