How exactly does one roll 1d500?

How exactly does one roll 1d500?

very carefully

Rolled 439 (1d500)

Here you go.

Roll a D1000, divide in half, round down

This method requires 3 10-sided dice. Yes, it technically isn't 1d500, but screw that.
So, the probability of getting any combination of numbers for 3d10 is roughly 1:1000 (10x10x10).
Treat each die as a digit, with 10 treated as 0 (resulting in a range from 000 to 999).
Divide the result by 2, rounding or truncating decimals as you see fit.

A d100 roll with 0 and 0 being zero zero
A d6 with 6 being 0.
Straight zeros are 500

i found this description but don't know how to make sense of it :

>Roll 1d500 (synthesize this by rolling a d10 and d%; if the d10 is 1-2, read the d% as is; add 100 if the d10 is 3-4, etc.)... you may need to roll on any of thirty or so subtables....

could some explain please?

Roll a d5 (1d10/2) then roll your D00 taking the 00 to mean 0 and the d10. boom.

You made me laugh

Roll a 5 on the d6 plus any of the 99 other results on the d100 and this fails. You are also twice as likely to roll 500 than any other number.

It's saying to treat the d10 as if it had five sides ranging from 0 to 4. The d10 is worth 100 times that value. Add the percentile die face straight to this number.

Or if you prefer.
(d10 divided by two [rounded up] minus one) times one hundred plus d100

3d10, halve hundreds die and round up.
If you only have a standard D&D set, roll percentile plus 1d6-1 for hundreds. This produced 0-499, special-case 0 as 500.

1d5 hundreds
1d10 tens
1d10 ones

1d500 = [1][2][3]

[1]: roll 1d6-1, reroll 6s
[2]: 1d10
[3]: 1d10

000 = 500

you roll a d100, then you roll a d5

just roll d100 for the tens and ones digits, then roll for how many hundreds (0 to 4)

>All these guys giving answers that net you a 0-599
Come on, Veeky Forums

Roll 2d10 for a normal 100 roll
Then roll (1d10 / 2) - 1. for the 1-500 range.

>year of Hijra 1439
>using physical dice other than d6

flip a coin as d2; on one side, +0, on the other, +250
then flip a second coin; +0/+125
this gives a range us 0,125,250,375 as outcomes so far, so we just need a way to generate another 0-124 as a range
we need all vals equally possible
roll a d5 and multiply by 25 to find which range to use, in multiples of 25 starting indexing at 0
for brainlets, here's a table:
d5 outcome : range
1 : 0-24
2: 25-49
3: 50-74
4: 75-99
5: 100-124
now repeat this d5 process to find a smaller rnage
for example if i got d5->1 earlier i'd now have this table for new d5 roll:
1: 0-4
2: 5-9
3: 10-14
4: 14-19
5: 20-24
you could alternatively convert these to +'s for simplicity
then simply use a d5 roll to determine final result
this is objectively the best way to roll a 1d500

>round down
You had one job

Roll 1d1000.
If it's over 500, subtract 500.
If it's under 500, keep it.
That's literally all you have to do.

1d5−1 hundreds + 1d100.

It's not that difficult, people.

Percentile dice themselves operate on the same "control die" principle. 1d10−1 tens + 1d10 gives a linear distribution from 1–100.

You roll a 5-sided die for your hundreds column (or just roll a d-6 and re-roll on 6), and then two D10s for the tens and ones column.

roll five of these babies.

is this actually objectively the best way to roll a 1d500?

Great, I can't get a result lower than 5 and my average result will be 247.5.

Roll d10 for ones place
Roll d% for tens place
Roll d6 for hundreds place, reroll on 6 OR roll d10 and divide by 2

Roll d1000 and cut in half with 1-2 = 1, 3-4 = 2, etc.

The d10 gives you a value of 0 (rolling 1-2), 100 (3-4), 200(5-6), 300(7-8) or 400(9-10).

Take the "base" number the d10 gives you, and add 1d100 to the result.

As such, you have generated a number between 1-500.

Perhaps an easier way would be to think that the d10 gives you the hundreds digit, and the d100 gives you the tens and units.

No. This is

roll 1d500

But who the fuck actually has a d5? I don't think there's any system that actually uses them.

1d6 reroll on 6

or 1d6 -1 if u need the 0

Roll D100 and D6. Substract one from the D6 number and multiply it by 100, add this the D100 number.

Obviously you don't if you'd otherwise be rolling a d5.

1d10 / 2, round up.

I have, like, twenty of pic related. Because I don't trust the funny-shaped ones.

There is one system that uses D5.