Find two numbers differing by 30 whose product is as small as possible

Find two numbers differing by 30 whose product is as small as possible.
I CANT FUCKING FIND THIS FUCK CALCULUS

x = 30
y = 0

29 and -1 fa.m

-15 and 15, retarded fucking niggerspeak poster

There is no number smaller than 0. By definition 0 is the smallest number. -29 is 29 units away from 0 and thus bigger.

I was pointing a countee example but you are right.
Wew lad

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15, -15

What about 100 and -70? What about x + 30 and -x?

no you autistic faggot read the thread before you count your siblings fucking useless nigger

O shit I'm sorry

Which community college do you go to OP?

That's two numbers differing by 30 with the *lowest* product, not the smallest.

The answer is 0 and 15 or 0 and -15

F(X) = x^2+30x
F'(X)=2x+30
0=2x+30

-->
X=-15

X+30=15

*0 and 30 or 0 and -30

john abbott, yes canadian
your answer is incorrect tho

thanks alpha

How is it incorrect?

isn't this pre calc?

No, you have to take the derivative of the function of the product of the 2 numbers and make it equal to 0, where the rate of change equals 0, aka, the relative minimum or maximum.

My precalc was basically learning all the rules and intuitive shit.

0 isn't a number - it's the concept of a lack of numbers.

No you don't "have" to do that. (a+15)(a-15) simplify.

Shitpost isn't a post - it's the concept of lack of information.

Are Lagrange multipliers precalc? That would be a pretty general and "proper" way to solve this, though pretty unnecessary desu.

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