What is 1/(-12) + 2/(-12) + 3/(-12) ... = ?

What is 1/(-12) + 2/(-12) + 3/(-12) ... = ?

The two triangles do not have the same area.

>Two triangles
Thats a triangle and an octogon m8

The two triangles have different inclinations.

1/(-12) + 2/(-12) + 3/(-12) ... = -1/12(1+2+3+4 ... ) =

negative-infinity/divergent, using the standard definition of infinite summation

or

1/144

using certain non-standard summation techniques.

Thats a triangle and an octogon m8

Hmm

(1+2+3+...)+2(1+2+3+...)+3(1+2+3+...)+...

Sum = x + 2x + 3x + ... (x = -1/12)
= x(1 + 2 + 3 + ...)
log(Sum) = logx + log(1+2+3+...)
= i*pi + 2*n*i*pi - log(12) + log(infinity)

Let n = (infinity)*i

log(Sum) = i*pi - infinity + infinity
(As, log(infinity) - log(12) is basically infinity)

Both infinities cancel by choosing an appropriate infinite value for n.

Hence, Sum = -1

QED

It's a quadrilateral and an octagon

Uh no the second one is a heptagon

The second one is heptagon

You know the hypotenuse is 2 sides, right?

its a quadrilateral and an octagon m8e

If you look very closely at the hypotenuse on the second image, it is not a straight line but actually bows out in a curve to account for the extra area that it contains.

Look, if you're still going to troll or act retarded, that's fine.
- Swear
- Ad hominem; Call people names
- Don't provide counter-arguments
- Reject realism and the scientific consensus
That's ok.
Just don't loop.
Looping is cancer.

Personal incredulity and the argument from ignorance are fallacies. You're ignorant.
You imply you have no knowledge of the other kinds, therefore they don't exist.
That is wrong irrational.
:D

Slope changes

Itll slowly approach negative infinity

Then the first one is a quadrilateral

We are discussing the red and blue triangles (which have different inclinations). Not the entire multi-colored objects they comprise.

Probably -infinity

Yes they do you tard