Just heard of this today, let's see what Veeky Forums thinks:
If you choose an answer to this question at random, what is the chance you will be correct?
A) 25%
B) 50%
C) 60%
D) 25%
Paradox
Oliver Moore
Michael Nguyen
0%, but it isn't listed.
Think outside the answer box, fuckhead.
Joseph Bailey
random? isn't it 25%?
Angel Robinson
It's 50%. Either you are correct or you aren't.
John Walker
Oh look, it's this thread again.
>C) 60%
You fucked it up, idiot. This option is supposed to be 0%. Pfft, brainlet.
Jack Wright
OP here; this was how it was presented to me
Juan Kelly
>assuming: the question given has anything to answer
>assuming: the question given refers to a random 4 choice question
not A&D because they are the same answer and "choose AN answer" implies you can only choose one choice (A OR D would be correct otherwise). this leaves you with %50 and %60 as the only viable choices. so %50 is correct I guess since the question only has 2 viable choices.
Luis Sanchez
what question?
Luis Cox
The answer is 0%.
The task implies that the answer to the question equals the chance of choosing the correct option (itself).
i.e. answer = prob of choosing that answer
If A/D is the correct answer:
The chance of choosing A or D is 50%. Since the chance of choosing the right answer is not equal to the answer this can not be the answer.
If B is the correct answer:
The chance of choosing B is 25%. Since 25% =/= 50%, this is not the right answer.
Same goes for C.
Since neither A,B,C or D is correct, therefore the chance of choosing the correct answer is 0%.
An easier version would be:
A) 25%
B) 50%
C) 60%
D) 0%
If A is correct:
A = prob(A)
25%=25% is True
This is an answer.
If B is correct:
B = prob(B)
50% = 25% is False
This is not an answer
Same goes for C and D.
Noah Lee
How many apples are there in a banana?
A) Orange
B) Green
C) Blueberry
Pineapple) D