Does anyone know how to replicate a ln(x) function using simple math?
Doesn't need to give a similar result mathematically, but the graph should look similar.
Basically making it peter out.
Math time!
Juan Price
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Chase Johnson
>not knowing about Maclaurin expansions
underage detected
Juan Taylor
>replicate a ln(x) function using simple math
>simple math
What does this even mean? Logs are literally basic arithmetic already.
Robert Scott
Do a fucking taylor series, you little bitch.
Or just do some type of root if you're just looking for diminishing returns
Justin Clark
[math]f(x) = \sum_{k = 0}^x 1/k [/math]
Lucas Watson
If you need it just for a short interval then you can use linear algebra to find an n-dimensional polynomial that approximates ln(x).
For this you would have to compute the values of ln for the points you want.
Also, this will not guarantee that ln(x)=p(x) where p is your polynomial, just that it will be pretty close.
This has a name but I cannnot remember so just google 'approximate functions using linear algebra' or something like that.
Aiden Brooks
[math]ln(x) = lim_{\epsilon \rightarrow 0}\frac{x^{\epsilon}-1}{\epsilon}[/math]
Isaac Hughes
>[math]ln(x) = lim_{\epsilon \rightarrow 0}\frac{x^{\epsilon}-1}{\epsilon}[/math]
Why didn't that render correctly?
Kevin Ortiz
Okay, lets calculate f(5)
Whoops, 1/k=0 does not have a value.
Oh. how dumb of me! You obviously need to take the limit as k approaches 0 for the first step. All right then
f(5) = +infinity
Hmm... I do not think that ln(5) = +infinity but oh well.
Jonathan White
It renders fine on TEX preview so Veeky Forums just wants to fuck with you.
Report to the devs or something.