Is this equation possible?

Hi Veeky Forums

could you help me out on this one please:
is it possible that

(1) a-b < c-d

and at the same time

(2) a/b > c/d

where a, b, c and d are from the one-dimensional Euclidean space of real numbers strictly greater than 1.
If this is possible, could you show me a proof or a link to a proof?
Best, Veeky Forumsaddict

no
a=2
b=3
c=8
d=6

a-b=-1 < c-d=2

a/b=2/3
c/d = 4/3
in fact this counterexample works for any a

Yes:

3-2 < 99 - 97
3/2 > 99/97

Great! Thanks so far! I get the counter example and the generalizaton of the counter example. Still, is there another "general" proof that would kind of rewrite equation (1) and show that if (2) was correct too, a weird contradiction would result?

The way you phrased OP you just wanted one example where it held, and
already delivered.

OP is fucking retarded

>in fact this counterexample works for any a

I was sure it can't be possible

the question as I understand it is "does the first line imply the second line, if so can you prove it".

Now I see that it can be understood as "is there an example of this situation", but it's not obvious which one OP was asking for.

So instead of being a dipshit, contribute or stfu.

It is pretty clear what OP says, we are contributing by calling on your crazy bullshit.

if you actually read the thread, you would see that I actually answered OP's question and that you're the one who didn't understand.
now go fuck yourself with a cactus, and get some lasik.

No, I am 8158073, you are the one who made a huge mistake and is now playing the game of who answers last because you are mentally ill. Most people will read the thread and realize that you are a retarded teenager lying to yourself on the internet.

you're right

No, the question is obviously asking for four numbers that satisfy both inequalities. Your reading comprehension is horrid.
"and at the same time" does not mean the same thing as "implies", I can't imagine in what world they are even close.

Hi all,
I am the OP. Thanks for the contributions :) Indeed, I was not completely clear in the original question. I meant to ask whether (1) and (2) are ALWAYS simultaneously true or not. So setting a

ah sure
well from 1

great - thanks! :)

No problem new friend :^)

>Impersonating someone else 4 hours later

samefag

how the fuck do you figure? do you even know what that word means?

Try harder.

off you go
your mommy needs you upstairs.

I'll give your Photoshop technique a 5/7

sure. How does it feel to be so useless you can't even spot a samefag? I mean you should just kill yourself right now and save your family the trouble of seeing you decay like the piece of trash you are.

Don't be so edgy, samefag.

kys
don't forget to stream it, I'd love to watch.

Wew lad

kys