1,5,17,48,122... what is the next number?

This.
You could just say the pattern is the zeroes of (x-1)(x-5)(x-17)(x-48)(x-122)(x-n) with n being the desired next number

Nope

Here's a clue.

Think about Fibonacci sequences.

>ITT

>Any fucking number you want. Literally any number.
>Kill yourself.
This.
Underconstrained problems are daily threads woo.

[math]p(x)=-\frac{3313}{1440}x^5+\frac{3365}{96}x^4-\frac{57353}{288}x^3+\frac{50843}{96}x^2-\frac{464621}{720}x+\frac{3397}{12}[/math]
p(0)=1
p(1)=5
p(2)=17
and so on

348

No, you're wrong.

it's 651

He literally just showed you how it could be any number at all. Mcfucking kill yourself dude

This is the right answer.

What kind of brainlet would be averse to pattern recognition? Of course it can be anything, but what's the simplest pattern?

I get 289

3397/12 != 1
obvious bait

>p(1)=1
>p(2)=5
>p(3)=17
fixed

"Simplest" is subjective, you fucking brainlet.

Not really, we all have a similar vague idea what it means.

It'll be 1 again. The sequence repeats after 122. Prove me wrong

I find a simpler sequence to have the least unique numbers, therefore is the simplest sequence to me.

266 given the input examples

You're being disingenuous.

I find 0.111111... repeating simpler than pi for the same reason. What is hard to believe about finding this sequence to be the simplest?

If this is continuous, it's definitely an exponential sequence.
Some form of a*2^x+b

How did you get to that solution?

he's OP

and he's a fag

Look up Lagrange interpolation.

Easy: number of times I've doggystyled your mom lmao

-1/12