Previous SQT thread maxed

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What about this guy? I got the first part right but I can't get the cos(x) correct. I tried doing a*b=|a||b|cos(x) where a and b are the values at the derivative and it doesn't work

What other value of t you got?

None

Oh, I got 3 and -7

Can you maintain a geosynchronous orbit at points other than the equator and what's the difference exactly between geosynchronous and geostationary?

Depending on your course, yes. If the course aims to teach proof techniques, then it's obvious that you would be expected to use those techniques on the test.

The point is developing your skills.

Geosynchronous means the time of orbit is 1 day. This is possible for an infinite amount of orbits, it does not have to be "parallel" to the equator it just has to be at the right distance away.

Geostationary means the satellite remains above the same spot on earth. You're still moving with some orbital speed, but that orbital speed matches the speed of the earths rotation. This is only possible if you're in geosynchronous orbit above the equator moving in the direction of earths orbit.

It's having an input that gives an undefined output. Like 1÷x and x=infinity. The function is indeterminant when x is zero, but we can see it approaches zero. y = 0 is the limit. But I'm just now taking calc I. I'm no math major.

For the tangent vectors, I get [-20,0,-10] and [20,0,110] with magnitudes 10*sqrt(5) and 50*sqrt(5), and dot-product -1500. So cos(a)=-1500/2500 = -3/5.