Do Veeky Forums even logic?

do Veeky Forums even logic?

Find the number for each sequence or are they connected?

i 4
ii 9
iii dunno

OP here. Each sequence.

...

I'm muy confusedo

iii is either 16 or 17

bump

the numbers 4, 8, 9 are the only numbers that appear twice in your matrix.

therefore the number 4+8+9 = 21 does not belong.

how did you get 9 on the second one

For each sequence:
i does not belong
ii does not belong
iii does not belong
My reasoning for this is that they do not share the same numeral system as the other numbers.

...

I think ii might be 8 because 19+9/2=14 and 19+14/3=11

4 because it appears twice
11 because it is prime
2 because it is the oddest prime

i
ii
iii

duh.

i is 4 (ill go with the appears twice logic)
ii is 19 ( 8, 9, 11, 14 is a sexy sequence- 1 2 3)
iii is 17 (2,7,9,16 is a sequence where the term is the sum of the last 2)

For i: 8 deceased by +1 each time. 4-0 then 4-1 then 3-2

1,2,3,?
find the next element in the sequence
SPOILER: it's [spoiler]4296829342985[/spoiler]

-
11
7

i) 0
ii) 7
iii) 8

i) literally anything if you give a reason why
ii) literally anything if you give a reason why
iii) literally anything if you give a reason why

i4, ii8, iii7

nah guys i) is the only one that's not subjective
8 = 4 + 3 + 1
4 = 3 + 1

No, it's actually a combination of two alternating patterns: where 'n' is starting at 1
8 - 5((n/2)-1) for every even number and
4^(1-(|n-2|)) for every odd number
4^1,8,4*1,8-5,4^0,8-10,4^-1,
4,8,4,3,1,-1,1/4,-6...

>(4^1),(8),(4^1),(8-5),(4^0),(8-10),(4^-1),(8-15)...

>yfw you spent all that time making an explicit formula for the series and you forgot that the point of the question is that one number is left out at the end

I only spent like 8 minutes. And I messed up with the formula. I was going to fix my error but I have other things I want to do... and other threads shit post in.

i 3 does not belong, it's the only prime.

15

Nope, it's 1 because that sequence is actually just zeros to y=(x-4)(x-4)(x-8)(x-3)

could you please explain it better?

But what if the sequence was the zeros to y=(x-4)(x-8)(x-3)(x-1) or any other arbitrary polynomial which contains those zeros.

cheggmate

i - 3, it's the only one that isn't a power of 2 (2^2, 2^3, 2^0)

i) 3 because it isn't a power of 2
ii) 8 because it doesn't contain an odd prime in its decomposition
iii) 17 because its prime factors are >9

sequences are infinitely long, polynomials can't have infinite degree