I'm dumb as fuck, ok? and i have an exam right now, since this one and s4s are the only intelligent Veeky Forums forums...

i'm dumb as fuck, ok? and i have an exam right now, since this one and s4s are the only intelligent Veeky Forums forums, i came here searching for help
you respond and i will keep posting problems

This is a very interesting number. It is the smallest number that can be written as the sum of the reciprocals of two consecutive even integers in two different ways.

and... what do that means?

Play around with any even number and it's inverse/reciprocal is just one over whatever number. The two consecutive even integers part of the problem a huge help with just straight out playing with numbers.

It's 10 and 12.

integers are 69 and 420

So n + n +1 = 11/16 2n +1 = 11/16 so 2n = 11/16 - 1 so n = (11/16)/2 - 1/2

thank you
i'm not that stupid

>since this one and s4s are the only intelligent Veeky Forums forums

>s4s
>intelligent

kek.

Look up the meaning of sum.
Look up the meaning of reciprocal.
Look up the meaning of two.
Look up the meaning of consecutive.
Look up the meaning of even.
Look up the meaning of integer.

There's your answer.

...

Nigger you're retarded, let me school you

[eqn]\frac{1}{n} + \frac{1}{n+1} = \frac{11}{60} \implies \frac{2n + 1}{n(n + 1)} = \frac{11}{60} \implies 2n + 1 = \frac{11}{60}n^2 + \frac{11}{60}n \implies \frac{11}{60}n^2 + \frac{109}{60}n - 1 = 0 \implies 11n^2 + 109n - 60 = 0[/eqn]

use quadratic formula
[eqn]n = \frac{-109 \pm \sqrt{109^2 - 4(11)(-60)}}{2(11)} = 0.52,\, -10.43.[/eqn]

pick either one as your first number, then add 1 to get the second number. thank me later