Log seems like rocket science to me

Hello, I am breddy gud at math but equations with log, ln, or e trigger the fuck out of me. I don't know why but I just can't seem to solve them. What are some good ways to simplify log-based equations?

You can represent logs as exponentials with unknown powers, that's all logs are for, but really what you need to do is just do more problems until you're comfortable with the functions themselves. If you're going higher than precalculus in math, I guarantee you will see log and ln in all of those math courses besides maybe statistics and intro to linear algebra. Do more problems.

>You can represent logs as exponentials with unknown powers
what did he mean by this?

> If you're going higher than precalculus in math
taking calc next semester tbhfam

graph it
its not that hard

>what did he mean by this

The definition of a logarithm?

Something that really opened my eyes was the realization that all the rules of logarithms are really just rules of exponents.
It took me an embarrassingly long time to realize that, but really helped me visualize and work with them.

e.g.
(e^x)*(e^y) = e^(xy)
ln(x) * ln(y) = ln(xy)

Did your teachers never tell you that logarithms are LITERALLY just the functional inverses of exponentiation? How the fuck do they introduce this material?

e shows up all the time in probability/stats courses

You literally solve them by putting everything that isn't log/ ln on the other side and raising the base of the log to the power of what's on each side. It's easy af to get rid of.

Stop trying to form shitty intuitions and just do the algebra.

You should probably understand what e's purpose is before you go online talking about it.

No fucking shit it shows up in statistics and probability. If we never dealt with exponential functions, we'd still be in the Stone Age.

You should be working on both. Build your intuition and your algebra skills/knowledge.
Having only one or the other will stunt your progress in the long run.

Basically like this:

Alright kids here's this cool new function called log. Make sure to memorize these properties of it. No we wont tell you why it works like this. All you need to do is know how to press the button that says log on your calculator. Oh and by the way it undoes exponets.

Just remember, the logarithm _is_ the exponent.

Like this

The logarithm is the exponent.The logarithm is the exponent.The logarithm is the exponent.The logarithm is the exponent.The logarithm is the exponent.The logarithm is the exponent.

is no one seeing this is totally wrong? (e^x)*(e^y) = e^(x+y)
ln(x)+ln(y) = ln(xy)

For the identity in the OP
[eqn]b^{\log_by}=y[/eqn][eqn]e^{\ln y}=y[/eqn]so[eqn]b^{\frac{\ln y}{\ln b}}=(e^{\ln b})^{\frac{\ln y}{\ln b}}=e^{\ln y}=y=b^{\log_by}[/eqn][eqn]b^{\log_by}=b^{\frac{\ln y}{\ln b}}\implies \log_by=\frac{\ln y}{\ln b}[/eqn]

whew, this seems to make a lot of sense. What kinds of practice problems would you recommend?

Are you working from a textbook? There's probably some stuff in there at the end of the chapter where logs are introduced. It should become second nature after a while.

If you're confused by an identity try doing it in terms of exponentials instead, it should make more sense from that angle.

thanks, op.
i always feel shit about sucking at math, but then i come to Veeky Forums, see threads like this and feel slightly better. i know i shouldn't, but i do.

I know how you feel OP

It's just your brain refusing to acknowledge the logic behind it. You must show it more proof - you must apply it as many times as possible to different stuff. Download Mathematica and start playing with equations, or just go to wolframalpha if you're too lazy for that.

You'll grasp it with practice - you'll surely understand it sooner or later after building enough neural connections relating to other abstract stuff.

Thanks!

ln(x) * ln(y) = ln(x+y) tho..
the same applies for
(e^x)*(e^y) which = e^(x+y) u retarded senpai

>ln(x) * ln(y) = ln(x+y)
That's completely wrong and it's so easy to show.

Let's say that [math]x=100[/math] and [math]y=1000[/math]. Using log base 10:[eqn]\log(x)\times\log(y)=2\times3=6\neq\log(x+y)=\log(1100)[/eqn]

Fuck, is this some new Veeky Forums meme?

Fucking triggered...you both are so wrong, gtfo this board if you can't do simple math.

But that's fucking wrong.

>ln(x) * ln(y) = ln(x+y) tho..
ln(x) + ln(y) = ln(x*y)

>ln(x) + ln(y) = ln(x*y)
>being literally this retarded

ln(x) + ln (y) is the same as ln (x) / ln (y)
Also, ln (x) - ln (y) = ln (x) * ln (y)

However, in the case of log this relationship is inverted so,

log x + log y = log xy
log x - log y = log x/y

do you even basic math?

sorry i didn't actually read the post on account of not being in fucking middle school anymore

This is literally grade 11 math. I taught Juniors in high school this shit when I was tutoring. Proof this board is retarded.

>grade 11 math
More like grade 9, dumbshit
>Proof this board is retarded.
It's just another shitpost/homework thread that doesn't reflect on the community itself. Clearly OP is an outsider. You're the retarded one

>I really want someone to take this bait

he fucked up it's

log(x) + log(y) = log(x*y)

I'm actually a biomed junior