Would this require a huge amount of energy?
Or just as much as a normal pump?
Would this require a huge amount of energy?
Or just as much as a normal pump?
It depends on the pressure, how much water you pump, and your definition of huge for energy
it would be extremely difficult
...
4u
Would depend on the difference, not the ratio
low pressure = 120 kPa
high pressure = 500 kPa
it was supposed to read 5 not 50 btw
typo
19kW
thanks
what equation did you use to calculate that?
is this per hour or per second?
proof that Veeky Forums was a mistake right here, ladies and gentlemen
wow.
ahah fuck
forgot W includes time haha
how about being helpful and answering this
wow
wowposters get out
i was just pretending to be stupid
multiply pressure differential by flow rate
thank you
Kys
If i was moot and i saw this shit id drop the board on the spot
.
Use P=∆P A v=∆P V/t
Ok
Power = Energy / time
Energy = force * distance
Force = pressure * area
=> Power = pressure * area * distance / time
Volume = area * distance
=> Power = pressure * (volume / time)
= (500e3-120e3) N.m^-2 * 50e-3 m^3/s
= 380e3 * 50e-3 = 19 kW
stop posting my waifu
I'd work, but I don't see the point
Why don't you just build a ham instead?
What's a ham? Is that some sort of American slang for something. I don't get it.
Or was it a typo and supposed to be dam?
Typo
>haha
do an energy balance