"worlds best math bot"
"worlds best math bot"
is the answer like 3 or 4?
Why would you ever use anything besides Mathematica?
it's not like the "answer" is any more simplified
its literally equal to pi
Pi. Consider the MacLaurin series for sin(x)/x and its Weierstrass product. Alternatively Fourier series can be used.
which makes it more simple how, because you used one meaningless symbol instead of 2
...
Hurr Durr look at me
A series is not a summation.
>meaningless symbol
what is the ratio of the circumference of a circle to its diameter
I can start computing the sum of inverse squares by hand pretty easily to get arbitrary accuracy of this number. Calculating digits of pi without knowing that summation I wouldn't know where to begin, I'd have to find some other summation to use.
A nonexistant value, since circles dont exist
I got sqrt(6). Fight me.
>circles dont exist
[math]\mathbb{Q}/\mathbb{Z}[/math]
Show me one, or even define one accurately
>define one accurately
A circle is a two-dimensional group of points in Euclidean space that are all equidistant from one other point in said space.
Given a point p, a circle of radius r is the set of all points x such that |x-p|=r.
Now, do circles exist in "real life?" Probably not, but I'd argue that 2 doesn't exist there either.
nice triplets
Cant argue with that.
is { (-1,0), (1,0), (0,-1), (0,1)} a circle ?
>he needs Mathematica for [math]\sqrt{6\, \zeta\left(2\right)}[/math]
A circle is what you get if you take an arbitrary point and reflect it on every line through the origin. I almost pulled a muscle trying to avoid definitions that could be connected to circles in any way.
>circles dont exist
typical finitist
mate the point of the thread was that some solvers couldn't do it, hence the guy showing Mathematica could