I'm very close to solving the "division by zero" problem. What is missing in my proof, Veeky Forums?

I'm very close to solving the "division by zero" problem. What is missing in my proof, Veeky Forums?

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definition of infinity

btw people who want to use numbers to measure things find it more helpful to have 0 * infinity = 0, jus sayin

I'm confused here. Is this idea that 0>0?

>assume that for any number >0 multiplied by inf = inf
Therefore 0 x inf = inf


>assume that for any number >0, 1/x = a real rumber
Therefore 1/0 = a real number

0.0000...1 isn't a number. You haven't proven that you can follow infinite 0s by an integer and still make sense of it in terms of the reals. To be more precise, you can't and it doesn't work in any field.

Either 0.00...1 = 0 or 0.00...1 > 0, you can't have both, retard

0.00...1 can be expressed as a limit and proven to be equal to 0. You're the real brainlet here since you're not even pretending

[eqn]
\lim_{x\to\infty} \frac{1}{x} = 0.
[/eqn]

The idea is that 0, like infinity, doesn't really exist, but he's doing it wrong.

Yeah I bet it can, go ahead and try.

Congratulations, you discovered hyperreal numbers. You have received a fields medal.

Here, I'll do it for you and then show you the problem:
[math]lim_{n\rightarrow \infty} \frac{1}{10^n} = 0.000...1[/math]

Your first problem is that this is equal to 0 in the limit, not greater than 0.
Your second is that if you define infinity as a limit, say
[math]lim_{n\rightarrow \infty}10^n= \infty[/math]
then the multiplication of the two might be expressed as
[math]lim_{n\rightarrow \infty} \frac{10^n}{10^n} = 1[/math]
or you could define it as just the limit of 5^n:
[math]lim_{n\rightarrow \infty} \frac{5^n}{10^n}= \infty[/math]

The problem is you can't actually multiply by a divergent series. There's no mathematical reason why you would be allowed to bring those definitions inside the same limit, otherwise I could come up with proofs that infinity equals every 0, 1, or probably anything I wanted it to be.

> 0 = .000...1 > 0

Fucking Latex copying, the last limit doesn't go to infinity it goes to 0.

>0.0000...1 isn't a number.
True, and it's terrible notation, but it's still understandable what it's supposed to mean: [math]\lim_{ n \to \infty } 10 ^{-n}[/math]

Did you pass highschool calc?

Did you pass *high school* at all? Also, I know it can be written as a limit because I wrote it as one: and showed you why your proof was stupid.

Also I should remind you that just because something can be written as a limit doesn't mean it's a number.

I'm not op, I only said that 0.00..1 is a number and it's the number 0

0.00..1 = lim = 0, are you saying 0 is also not a number?

I meant that it's not a number different from 0, sorry it happens to be 3:40am here. And by the way, I did pass high school calc.

With respect to that specific comment I'm saying that I can easily write a divergent series that doesn't represent any number.

0.000...1 doesn't exist genius

Prove it.

>infinitesimal = 0
wew

The burden of proof is on you to prove that it exists

It does and someone even posted it already in this very thread

[math]lim_{n\rightarrow \infty} 10^{-n} = 0.000...1 = 0[/math]

Have you heard of hyperreals/infinitesimals?
They are very small values, small like 1 over infinity small, but they can not be represented by simply a 0.

Have you heard of hyperinfinity?
It can crush hyperreals.

Oh wait that's just infinity.
Simple crude badass infinity, the kind non-autists use.

1/inf = 0

Infinity is not a number

According to Rudin 0 x infinity = 0

Infinity/infinity=0
1=0

0*infinity=1

6/10/18

7:8:9

9 doesnt exist

because 7 8 9

all the proof you need is here Kal-El
7:8:9

wake up

youtube.com/watch?v=D3-eRt_c-d0