Why is (x^2)^4 = (x^4) and not (x^8)?

Why is (x^2)^4 = (x^4) and not (x^8)?

because someone made a mistake

(x^2)^4 is equal to x^8

x=1

Could you explain how X=1 would make that true?

25% correct
x={±1,±i}

1^n=1
1^8=1^4

100/2n% correct
x={±1,±i,±j,±k,±l,±...±n}

fucking kek

Literal facepalm on this. It's supposed to be true for every value on the variables. It's an arithmetic rule not an equation. Sorry if incorrect terminology as english isn't my native language.

this

Actually, [math]{x^2}^4=x^{2^4}=x^{16}[/math]

"roots of unity" would make a decent name for some pagan whatever band.

It's wrong dumb shit

go to a real university next time

False [math] (x^2)^4=x^2*x^2*x^2*x^2=x^8 [/math] It's like you don't even know what a logarithm is.

Yes I know OP's picture is wrong, he was trying to justify it saying it's right. You can never solve for a value on x and y in OP's pic so you have to give an answer true for every value. He said it was true for x=1 which is true but it is still incorrect.

Actually, he's more like 20% correct.
{0, +-1, +-i}

Why do people put "+-i"? Isn't the whole point of imaginary numbers that they don't have properties like + or - and therefore they can for example have a negative square? The way i was taught you shouldn't do it.

Oh sorry, I forgot that the complex numbers doesnt form a field, my mistake

what the fuck

Polish understand that -0 is a multiplier.

i'm a 20 year math professor and this is correct

No... For example (-i)^3 = -i^3. Thinking it on 2d plane minus is a pi turn.

Nice bait dude.
[math]log(x^2)^4=4logx^2=8[/math]