If c*a = b*c, then a = b ?
If c*a = b*c, then a = b ?
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Yes because you can divide the equation by c.
Fucktard.
u can divide only if u know that G is commutive, otherwise not at all
Yeah, but if it is a non abelian group?
Not if c is the multiplicative identity :^)
Also, so long as c =/=0
with multiplication notion there is no 0, basic group propertys u fucker
>basic group propertys
>no 0
you retarded, senpai?
with "*" 1 is used as identity, with "+" 0, G is said to be group not ring
OP indicated that the group operation is multiplication. Hence [math]0[/math] can't be part of the group because there's no inverse element [math]0^{-1}[/math] such that [math]0*0^{-1}=1[/math].
It's really not specified what set we're dealing with, so I guess one could invent an inverse to 0 if they really wanted to. That's a bit beyond me though.
fuck no, a=c^{-1}bc
No unless your group is Abelian.
Then b=c*a*c^-1, and the rest depends on whether a and c commute.
>a=c^{-1}bc
This.
You have equality iff c*a = a*c. Also iff c*b = b*c.
Also, for the Rubik's Cube group, it should be obvious that [math]c^{-1}bc[/math] is often different from [math]b[/math]. You should be familiar with what transforming [math]b \to c^{-1}bc[/math] does, as it is important for solving the thing.
If G is abelian, then yes. If G is nonabelian, then this doesn't hold for arbitrary a,b,c.
For a nonabelian example, you can find a,b,c in S_3 quite quickly that satisfy ca = bc but a is not equal to b.
Extra little note: if a group G has the property that ca = bc implies a=b for any a,b,c in G, then G is abelian. That's a nice little exercise that's easy if you can work through the logic.
Even if you were working in a ring, you have problems with c=0 and zero divisors.
It's true if a,b, and c are the only elements in the group.
thanks dude. I was looking for a counterexample.
>fucktard
If and only if * is commutative, simplifiable and c is not an absorbing element of *.
Any other reply is brainlet-tier.
I think quaternions are a counterexample.
>the only group I know are the reals
Fucktard.
>high-schooler
leave Veeky Forums forever
...
>If c*a = b*c, then a = b ?
Only in an abelian groups, but for matrices a and b are similar, which is an equivalence relation too.
*provided c is regular ofc