Which would show a greater reading on the scales, or would they be the same?

Which would show a greater reading on the scales, or would they be the same?

What? The scales would read the same.

What do the scales measure?

What if they had the same contact area, but A went higher? Wouldn't it exert greater pressure?

If the volume of water is the same then they would read the same. The density of water is constant at 1000kg / m^3

A cube of water with dimensions 1m x 1m x 1m has a weight of 1000kg.

A would be slightly less than b due to the difference in height of the water, but as long as the column is less than 100 feet or so, it wouldn't be a big difference

B would be higher since the center of mass is closer down. Gravity would be pulling it down more since it's closer to the center of the earth.

then its not a set of scales -- its a pressure gauge connected to two vessels. Its misleading to use the word scales which are assumed to measure weight or mass.

Kg is a measure of mass, not weight.

No, I mean scales, would the higher pressure at the bottom affect the reading?

No.
The pressure at the bottom of a is greater than the bottom of b.
But the pressure at the top of a is less than the top of b so it evens out.

>But the pressure at the top of a is less than the top of b
But they should both start at 0 pressure at the top and scale linearly at the same rate as you go down.

Volume of the container:
[math]V_{container} = \pi r^2 t + 2 \pi r h t[\math]
Where r is container radius, h height, t thickness.

Volume of water:
[math]V_{water} = \pi r^2 h \rightarrow h = \frac{V_{water}}{\pi r^2}[\math]

For a given container radius, the container volume is then:
[math]V_{container} = \pi r^2 t + 2 t \frac{V_{water}}{r}[\math]
Showing that the container volume increases with radius. Therefore option B has more mass.
Which option would "show a greater reading on the scales" would be affected by how they were zeroed, calibrated, etc.

This assumes that the thickness of the container is the same on the bottom sections as the sides, along with a number of other minor assumptions.

*scrolls down Veeky Forums*
*sees this thread*
*keeps scrolling down*
*decides to scroll back up*

it depends on a bunch of different variables of which you have failed to give, faggot

*keeps scrolling back down*

this isn't your blog. At least attempt to be useful.

*tabs back to this thread*
*scroll down*
*see your shitty post*

You're a faggot.

*tabs back to gay tranny midget porn*

>*tabs back to this thread*
You said you scrolled back down after your first comment, you fucking liar.

Huh? I tabbed back, and it was already scrolled like halfway up. I saw that there were more posts in the thread so I scrolled down.

You're panicking, sir, the story keeps getting more complicated.

*teleports behind you*
heh, nice post kid
*splits you in half with my 1000 folded katana*
pssh, nothing personnel

What is air pressure?

Greater pressure, but a correspondingly smaller area and thus the same force.

>[\math]
nope it's [/math]

Listen to this guy

same, but if you want to get really fucking obnoxiously autistic then B, because more of the water is closer to earth and so gravity is slightly slightly slightly more powerful

Unless the scales are stupidly precise they will show the same weight

You are thinking of pressure entirely wrong.

Yes the pressure at the bottom of A is greater than at the bottom of B. However, pressure is not a downward force. It acts in all directions. It pushes down against the bottom of the container, up against the water and air above, and against the sides of the container. However these forces stop at the boundaries of the container. The scale is on the outside of the container and is therefore unaffected by the water pressure.

This

What's a measure of weight?

Are you serious? Newtons.

oops

the same, B would read more if it was wider than the scale

This seems correct to me, thanks.
They could have the same area at the bottom and still go to different heights though, something like Gabriel's horn.

holy shit this isn't bait....

B would be slightly heavier, even thaving he same volume and mass, because the center of its mass would be nearer the center of Earth, and F=GmM/d2