Can't find x&y

Seems easy

x=5, x^2 = 25, y = 6, x^2+y = 25+6=31

5+(36)=41

x = 5
y = 6

/thread

Good, now prove it's the only solution

I'd say "first post, best post" but there should be at least four answers.

what's the file name in the OP in English?

goy pussy is for god's people

8367463
(You)

It's "untitled.png".

ye its untitled.png

Never have I been happier that my calculator has a "solve equation" button.
Answers:
(5,6)
(-4.9217317, 6.7765575)
(-6.153604, -6.8668482)
(6.0753361, -5.9097093)

y=31-X^2
x+(31-x^2)^2=41

Is it that hard?

This is literally middle school math. How can it be that hard?

ye... i wanna do it without a calculator

Go on

Solve for x you dip?

x+31^2-62x^2+x^4-41=0

I swear to god this damn board is full of retards.

You are retarded.

Have you solve it yourself yet....?
ass

have fun solving that quartic without a calculator

>not evaluating 31^2-41in your head
>not ordering the variables by their powers
shoo

...

Don't wanna do too many steps all at once, poor OP's brain might implode.

well just showing them a seemingly random quartic doesn't exactly help them but alrighty, Veeky Forums never has been helpful to high school kiddies

...

lol this is not H.M
i've finished school

just sharing a nice problem

Obviously