A 5 meters long rope is tied to two trees that are 4meters apart. A mass of 70kg is placed on middle of the rope.
a)Calculate tension of the rope.
b)If the tension was 1352N, what would be the shortest length of the rope that could withstand it.
>Are the right answers?:
>a) T=2.5N ( prob wrong by far)
>b) l(min) = 0.8m
Are you fucking retarded?
Calculate the Lagrangian and let me know what you get so I can help
>No, just not good at math
>im perfectly aware how theory works, but dont know how to calculate it
>Not sure what Lagrangian is.
As the angle is unknown but we have simmilar triangle i tried with cos(alfa)=Txl/TL(where Txl is x component of TL)
Indeed wrong by far. Use the law of sines.
a) T= 3939N
Does the angle stay the same in b)? Im too lazy to think
Yes it stays the same, Thank you for advice.
Well then your b) is pretty much correct. I got 0,85m.
Might be wrong way to do it.
I did it so:
Tcos(alfa)=TxL
and as TxL/T = d/2 / l/2 i got l/2 = TxL / d/2 * T
>Btw. do you get angle of 36.87° ?
Yeah uh I just realized my mistake
x/1352 = 5/3939
x = 1,7m