2+2=5 explain this Veeky Forums
2+2=5 explain this Veeky Forums
Operations done on one side must be done on all terms, so if you square root the right you have to include that +9/2 in the root.
wrong from the second line. because 4
it's that a tattoo? cause it looks like a tattoo
>you have to include that +9/2 in the root
no you dont
right for the wrong reason
The problem is that sqrt((4-9/2)^2) (which results in +1/2) doesnt equal 4-9/2 (or -1/2).
>right for the wrong reason
what I said implies what you said. brainlet
This. They're ignoring a +/- that comes with a square root.
4-(9/2)=-(5-9/2)
>:P
math is fake
ikr
seems like they didnt get the joke. never mind.
How do you come up with shit like 4 - 9/2 + 9/2
Are you retarded?
wow ebin math :DDDD
0 = 0
0 = 0 - 1/2 + 1/2
= sqrt[ (0 - 1/2)^2 ] + 1/2
= sqrt[ (-1/2)^2 ] + 1/2
= sqrt[ 1/4 ] + 1/2
= 1/2 + 1/2 = 1
broof that 0 = 1 xD
you just look for a point that is equidistant to 4 and 5
Second line falsely assumes sqrt(x^2)=x
When in fact sqrt(x^2)=abs(x)
1/10 - at least it's not "0.999...=1?"
XD math is a hoax
this faggots matematicians say that 1+2+3...= -1/12
so whatever
>squaring and square rooting only part of the right-handside of the equation
that's not fucking legal
bann the negaters
sqrt((4-9/2)^2) /= 4-9/2
you are basically adding 1 to it with between the square and absolute value
I am irrationally angry for it being wrong in the second step. Fuck you for not even making it worth exploring.
It's wrong because [math]\sqrt{(4-\frac{9}{2})^2}=\mid4-\frac{9}{2}\mid[/math]
[math]4-\frac{9}{2} < 0 [/math]
So:
[math]\sqrt{(4-\frac{9}{2})^2}= |4-\frac{9}{2}| = \frac{9}{2} - 4 \neq 4-\frac{9}{2}[/math]
thats your mistake
thanks for showing this.
it doesn't matter that like 8 people pointed out the same elementary mistake
This is actually right, it has been proved by general relativity that all numbers are actually relative. I bet that paper was in an accelerated frame of reference
Elaborate please.
>tfw to smart too do maths