2+2=5 explain this Veeky Forums

2+2=5 explain this Veeky Forums

Operations done on one side must be done on all terms, so if you square root the right you have to include that +9/2 in the root.

wrong from the second line. because 4

it's that a tattoo? cause it looks like a tattoo

>you have to include that +9/2 in the root
no you dont

right for the wrong reason

The problem is that sqrt((4-9/2)^2) (which results in +1/2) doesnt equal 4-9/2 (or -1/2).

>right for the wrong reason
what I said implies what you said. brainlet

This. They're ignoring a +/- that comes with a square root.

4-(9/2)=-(5-9/2)

>:P

math is fake

ikr

seems like they didnt get the joke. never mind.

How do you come up with shit like 4 - 9/2 + 9/2

Are you retarded?

wow ebin math :DDDD

0 = 0
0 = 0 - 1/2 + 1/2

= sqrt[ (0 - 1/2)^2 ] + 1/2
= sqrt[ (-1/2)^2 ] + 1/2
= sqrt[ 1/4 ] + 1/2
= 1/2 + 1/2 = 1

broof that 0 = 1 xD

you just look for a point that is equidistant to 4 and 5

Second line falsely assumes sqrt(x^2)=x
When in fact sqrt(x^2)=abs(x)
1/10 - at least it's not "0.999...=1?"

XD math is a hoax

this faggots matematicians say that 1+2+3...= -1/12

so whatever

>squaring and square rooting only part of the right-handside of the equation

that's not fucking legal

bann the negaters

sqrt((4-9/2)^2) /= 4-9/2

you are basically adding 1 to it with between the square and absolute value

I am irrationally angry for it being wrong in the second step. Fuck you for not even making it worth exploring.

It's wrong because [math]\sqrt{(4-\frac{9}{2})^2}=\mid4-\frac{9}{2}\mid[/math]

[math]4-\frac{9}{2} < 0 [/math]

So:

[math]\sqrt{(4-\frac{9}{2})^2}= |4-\frac{9}{2}| = \frac{9}{2} - 4 \neq 4-\frac{9}{2}[/math]

thats your mistake

thanks for showing this.
it doesn't matter that like 8 people pointed out the same elementary mistake

This is actually right, it has been proved by general relativity that all numbers are actually relative. I bet that paper was in an accelerated frame of reference

Elaborate please.

>tfw to smart too do maths