ITT brainlets are exposed

Hello fellows brainlets Veeky Forums posters, I am a brainlet too and I'm here to expose you all. Do not bet afraid to expose yourselves, we are all anonymous here, come and join me in the brainlet club.

>Picture totally related

Come on friendos, don't be frightened to show your inner retardation

Come on guys, will you leave me alone in the brainlet club?

I honestly have no idea

Its ok friendo, I got that wrong too, welcome to the club!

On average, c, since the flies exert a force on the air inside which in turn exerts a force on the bottom of the jar

Totally d
B, the escaping gas

1. sitting at the bottom
2. moving to the right
3. dont know

Gonna say b, might be wrong

more force than 5 lbs would definitely be needed to maintain the strands horizontally, so it's either 10 or 20

Dude exactly horizontally you have to apply infinite force. The force upward is 2Tsin(theta) so if theta is 0 t is infinite

C

If the jar had vacuum inside, then A.

Not OP, but all of these are from a book called "Thinking Physics" if anyone is interested. The entire book aims to teach 1st +2nd years physics using only problems like these. (intuition rather than equations)

Congrats! You're not a brainlet(yet)!

Welcome to the club!

b c d a?
t. 18yo

sheiiiit. How did I not notice that?

No?

Better grip, but the force is still the same, so B?

2 right 2 wrong! Welcome!

This guy right here knows what's up!

no

Good boys!

That depends, is there air inside the jar. The flies won't add to the weight measured if they fly in the vacuum.

The scale shows highest weight when flies are flying up, average is still the same.

Flies in the air is buoyancy + wingclap, buoyancy is same as sitting on bottom and wingclap can only contribute positively to the sum. So flies in air weigh more than when sitting on floor.
>inb4 they weight nothing when not clapping wings
Bullshit, that's only in free fall, and they're not in free fall between claps.

Please explain to me how the fuck they would fly in a vacuum

Well the flies would have to exert a downward force on the air in order to fly. The force would have to be greater than or equal to the weight of the fly.

The force would create turbulence in the air. I don't think its safe to assume that the force exerted by the wings would directly translate to an equivalent force on the ground, although its likely that there would be some, small amount of impact.

So the force would probably be largest when the flies are sitting at the bottom of the jar.

Dumb trumposter

When flies are on the ground minus negligible buoyancy they need a normal force equal m*g or Fn.

When they are falling, they have air resistance of Fa. Now get it but Fa to equal Fn requires it ot be equal m*g. So it means it's only equal if air resistance can keep the fly not moving. Which means it's only true if the air is so dense the flies can't fall down.

F=ma, if the fly isn't moving along the y axis the force he exerts is 0
the fly will be infinitesimally heavier when taking off and flying upward, and have the same weight when hovering

im pretty sure it would be moving to the right because to conserve the momentum of air molecules rapidly flying leftword it would hvae to cancel that and move to the right, assuming it's on frictionless surface,.

only physics background is AP Physics in hs tho

a because the air will push the can to the left

C because it says after

not if its in space. the net force will be zero so it will maintain a constant velocity.

It will slow down eventually so if you want to be like that then it doesnt specify how long after

ok then what if it's a perpetual motion device

c
c
d
b
b

20 lbs would be at 14° rope angle.
So... it must be d then.

This reminds me of that Feynman story about the submerged nozzle, it's in Surely you're joking.

If I'm a "coder" and have a high IQ but I have minimal math knowledge, am I considered a brainlet?

yeah but the pressure on the side with the opening will be greater because it sucks fluid/gas towards it

maybe it depends on the fluid/gas

C

The pressure is just the byproduct of gas molecules hitting the walls and bouncing off, transferring their momentum to the object. If we punch a hole in it's true that gas molecules will put much greater pressure on the left wall thanks to smaller area of the right wall, but the momentum of molecules that would be normally hitting the right wall instead went inside. The "balls" that normally would balance the force on left wall are now inside and their momentum after some time will hit the left wall from the inside. After the vacuum fills the chamber, the chamber will gain momentum [math]p_0[/math] from unbalanced force on left wall, and momentum [math]p_1=p_0[/math] from the air molecules entering through the puncture. Effectively making it stop.