You should be a le to solve this

>you should be a le to solve this
>are you smart enough?

Get the fuck off with your calculus II homework, you clueless brainlet. My 185 IQ is triggered by such a retardation, I can't fucking believe it. Kill yourself you retarded faggot.

This board isn't for posting your homework OP, especially homework that easy.

0, am i smart now Veeky Forums ?

>Integrating an anti-symmetric function over a symmetric interval.

what is this shit?

'U' can do this op

>0

It's 0.5, brainlet. You have to consider the area underneath x-axis as positive

>You have to consider the area underneath x-axis positive
"No"

What if he substitutes another variable name?

You should know the derivative of sin^2 (x) just from experience desu

>picture of the screen
>brainlet
every time

Why? Areas are intrinsically positive..so you do two intergral of 0 to pi/2 and 0 to -pi/2 and the modulous is added

looks like a cartoon character

1/2

did i do it right

I'd just like to interject for a moment. What you're referring to as calculus, is in fact, real analysis, or as I've recently taken to calling it, [math]\left( \mathbf R,\, +,\, \times,\, \leqslant,\, \left| \cdot \right|,\, \tau \,=\, \left\{ A \,\subset\, \mathbf R \mid \forall x\,\in\, A,\, \exists \varepsilon \,>\, 0,\, \left] x \,-\, \varepsilon,\, x \,+\, \varepsilon\right[ \,\subset\, A \right\},\, \bigcap_{\begin{array}{c} A \,\sigma \text{-algebra of}\, \mathbf R \\ \tau \,\subset\, A \end{array}} A,\, \ell \right)[/math]-analysis. Calculus is not a branch of mathematics unto itself, but rather another application of a fully functioning analysis made useful by topology, measure theory and vital [math]\mathbf R[/math]-related properties comprising a full number field as defined by pure mathematics.

Many mathematics students and professors use applications of real analysis every day, without realizing it. Through a peculiar turn of events, the application of real analysis which is widely used today is often called "Calculus", and many of its users are not aware that it is merely a part of real analysis, developed by the Nicolas Bourbaki group.

There really is a calculus, and these people are using it, but it is just a part of the field they use. Calculus is the computation process: the set of rules and formulae that allow the mathematical mind to derive numerical formulae from other numerical formulae. The computation process is an essential part of a branch of mathematics, but useless by itself; it can only function in the context of a complete number field. Calculus is normally used in combination with the real number field, its topology and its measured space: the whole system is basically real numbers with analytical methods and properties added, or real analysis. All the so-called calculus problems are really problems of real analysis.

...

>2.5 = 1

multiplication.

If you have to ask why you don't understand integration, and shouldn't be calling anyone a brainlet, brainlet.

TIL Veeky Forums doesn't know trig identities. This is just 1/2 sin (2theta) which obviously integrates to 0 with an interval symmetric about the y axis. No u sub necessary.

Use parentheses you dork.

integral -pi to pi odd function*even function = integral -pi to pi odd function = 0

I've never been able to remember any of them and at this point it feels way too late

0. The sin and cos are orthogonal.

Is this a joke?

(1/2)sin (x)^2|(pi/2,-pi/2)

(1/2)sin (pi/2)^2 - (1/2)sin (-pi/2)^2
.5 -.5
0

t. Highschool calculus student