Last /sqt/ is autosaging.
/sqt/: Stupid Questions Thread
Ethan Powell
Camden Barnes
Reposting my q
Aiden Hill
Seroius question: what is the average diameter of the human penis when erect
Caleb Miller
Integral of the diameter over the length of the penis, divided by the length of the penis.
Hunter Reed
Nigga u dum. dats da average diameter of A human penis, not THE human penis.
Logan Scott
How do you use figures from other papers? Do I just screenshot them and give credit in the figure caption? I don't want to believe that I have to email the authors of each publication to use them. If it matters, the papers are typically published on arxiv so very open
Charles Hernandez
anybody doping biophysics here? how do you like it?
Luke Anderson
THE human penis is my penis and I can confirm user is correct
Justin Young
Copying my post
Someone wanna explain how to use the normal form of a transition matrix to solve differential equations?
Currently working on
[eqn] \ddot{x} + 2 \dot{x} + x = 0 [/eqn]
Letting [math] v := \dot{x} [/math], gives
[eqn]
\begin{pmatrix}
\dot{v}\\
\dot{x}
\end{pmatrix} =
\begin{pmatrix}
-2 &-1\\
1 &0
\end{pmatrix}
\begin{pmatrix}
v\\x
\end{pmatrix}
[/eqn]
Letting the matrix equation be [math] \dot{X} = A X [/math]
The characteristic values are both 1.
And that's about as far as I can get with repeated characteristic values.
How do I find the rotation matrix P such that
[math] P \dot{X} = P A P^{-1} P X [/math]
I know that the normal form of A should be given by
[eqn] J = P A P^{-1} = \begin{pmatrix} 1 & 1\\ 0 & 1 \end{pmatrix} [/eqn]
and that if I find P, I can define U such that [math] U = P X [/math],
and use some easier differential equation solutions to solve the new [math] \dot{U} = J U [/math]
Alexander Brown
How often do you masturbate? Do you find it easier to study when you masturbate frequently or when you abstain?