Approximating π

Cool, thx
(I see ", Integers" also works with Solve)

found this solution as well

[eqn]\frac{312689}{99532} = \frac{3}{4} + \frac{144}{149} + \frac{238}{167}[/eqn]

>within one-half part per trillion
>it's only ~39 ppb by my calculation
We were both wrong, it's 39 per trillion.

I'm a rebel
[eqn]\frac{22}{17} + \frac{37}{47} + \frac{87}{83}[/eqn]

>french
>page in the background literally says croissante
Really makes you think.

here's the solution I found with some modular algebra:
[math]208341=(47)(83)A+(17)(83)B+(17)(47)C[/math]
remainders on division by 17:
[math]6 \equiv 8A(mod~17)[/math] so A = 5,22,39...
remainders on division by 47:
[math]37 \equiv B(mod~47)[/math] so B = 37,84,131...
remainders on division by 83:
[math]11 \equiv 52C(mod~83)[/math] so C = 5,88,171...
picking B = 37 (for example) gives the choices
(A, C) = (5, 171), (22, 88), (39, 5)

>3.1295444607
Pi as fuck.

>Joke's on you I was only pretending to be retarded