what's the radius of ths inscribed circunference?
I'm a fag
About 2.485
3sin (1/pi)
i meant (1/4)pi
r+r*sqrt(2)=6
Take the diagonal radius of the big circle.
6 = r + r * sqrt(2)
r = 6 / (1 + sqrt(2)) = 2.485, which is what said
where does the sqr(2) come from
Actually I'm wrong didn't look at the pic
the diagonal part
I don't get it
These are correct. I took a coordinate geometry approach that was probably a bit overkill
After looking at what I did and comparing it to this
I realize what a fag I am for not seeing simple geometry
imagining the red line i got 6/sqrt(2)/(1+sqrt(2)/2) without even using a piece of paper
The rightmost "r" is at an angle of 45 deg, 6-r-r*sin(45 deg) = 0.
About three fifty
How do you prove it's 45*
are you all retarded or am I?
How is 6 not more than 2r
Are you serious? It starts at the radius and bisects the 90 degree angle between the bottom and side.
>starts at the radius
I mean starts at the center of the circle.
ok yeah im retarded
in other words, its is not possible because radius of a smaller circle can't be >=6.
>it's impossible for a circle to fit inside a quarter of a circle
Also, I can't read your = arcsin(?) part, so I can't tell what error you've made.
6/(1+φ)= 2.29179
noobs
6/(1+√2)=2.485281