I'm a fag

what's the radius of ths inscribed circunference?

About 2.485

3sin (1/pi)

i meant (1/4)pi

r+r*sqrt(2)=6

Take the diagonal radius of the big circle.

6 = r + r * sqrt(2)

r = 6 / (1 + sqrt(2)) = 2.485, which is what said

where does the sqr(2) come from

Actually I'm wrong didn't look at the pic

the diagonal part

I don't get it

These are correct. I took a coordinate geometry approach that was probably a bit overkill

After looking at what I did and comparing it to this
I realize what a fag I am for not seeing simple geometry

imagining the red line i got 6/sqrt(2)/(1+sqrt(2)/2) without even using a piece of paper

The rightmost "r" is at an angle of 45 deg, 6-r-r*sin(45 deg) = 0.

About three fifty

How do you prove it's 45*

are you all retarded or am I?

How is 6 not more than 2r

Are you serious? It starts at the radius and bisects the 90 degree angle between the bottom and side.

>starts at the radius
I mean starts at the center of the circle.

ok yeah im retarded

in other words, its is not possible because radius of a smaller circle can't be >=6.

>it's impossible for a circle to fit inside a quarter of a circle
Also, I can't read your = arcsin(?) part, so I can't tell what error you've made.

6/(1+φ)= 2.29179

noobs

6/(1+√2)=2.485281