How do I solve this?

The answer is 3x root2

nope
/r9k/ may work for you though

sqrt(2)+sqrt(8)

Or you can perform the square and get sqrt(2+2(4)+8) = sqrt(18) = 3sqrt(2)

>all these brainlets saying sqrt(x^2)=x and not |x|

[math]\sqrt(\sqrt2+\sqrt8)^{2}[/math]
[math]\sqrt(2+\sqrt16+8)[/math]
[math]\sqrt14[/math]
I felt ridiculous typing this out.

>[math]\displaystyle\sqrt{\left(x^2\right)}=-|x| : x\in\mathbb{Z^+}[/math]
Yeah okay.

It's [math]\displaystyle2\sqrt{16}[/math]

even more ridiculous when you got it wrong senpai

kek

The sqrt cancels the square.

You're left with sqrt(2)+sqrt(8)

Which is equal to sqrt(2)+2sqrt(2)

combine terms, 3sqrt(2)

You're an asshole. I like u tho.