like this maybe?
I only skipped the calculus part and if I made any mistakes then the real problem probably isn't much harder as they should just be some small ones regarding factors and that.
An isosceles triangle is drawn around a circle...
Sure, but then it couldn't be isoceles.
An isoceles of this type is clearly not the smallest possible area. Which was assumed, so no need to consider it.
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sorry, I should have been more exact with my sarcastic greentext
>An isosceles triangle is drawn around a circle. Prove that the triangle is also an equilateral triangle assuming that the area of the triangle is the smallest area possible.
>suppose it's not equilateral, then one of the bases is not tangent to the circle
>image of non equilateral triangle with each base and edge tangent to the circle
First tell me how you drew it.
Again, it's obvious that a right triangle with tangent bases is going to have an area greater than an isoceles where one of the bases isn't tangent. Since it was assumed that the triangle was smallest area, all right triangles can be ignored. My original post wasnt a complete proof, just an outline of how to go about it.
Shut the fuck up retard, you're wrong