Sup /sci, I saw this a while back on /b and never got the answer. Any theories?

How?

Could it be infinite?

Because googling the answer said so.

Drawing in the four red lines divides each quadrilateral in the original shape into isosceles triangles (blue) and a second triangle (white). The four isosceles triangles are identical.

With the inclusion of the red lines you have four triangles with identical base of the red line. The area of a triangle is found by 12×base×height 12×base×height. Using this to calculate the sum of the area of two triangles directly opposite each other you will get 12 times the length of the red lines squared. Then you can add the identical green triangles onto this to get the following: 32+16=20+?32+16=20+? resulting in an answer of 28.

Let P be that interior point of the square where all the segments meet.

Now draw line segments from P to each corner of the square. Say the square has side length 2x.

Now the square is divided into 8 triangles. Each of the 8 triangles has a side of length x.

Now each of the known areas is the sum of two triangles. Use this to set up a system of equations. You should be able to solve for the unknown area.

its 26 brainlet

no it could not.

The top right and bottom left add up to 48. If you move the middle vertex diagonally up-right, into the centre, now you have two identical perfect squares whose combined area is 48 so each is 24cm2.

This also made the 20 area into another identical square. Clearly the whole square is 96 cm2, subtracting 20, 32 and 16 leaves 28

...

There's no reason that this would be true. You seem to be implying that those are isosceles triangles but really they're both just scalene

same base and height...