Well Veeky Forums?

>computation time exceeded

Obviously there are an infinite number of solutions.

Instead of using the silly fruit notation, write it as:

[eqn]{x \over (y+z)} + {y \over (x+z)} + {z \over (x + y)} = c[/eqn]

Then, using some arithmetic, you can express x, y, or z in terms of the two other variables and c. So long as no pair drawn from x, y, or z sum to 0, you can freely choose two variables and calculate the third based on the relation.

why do this when you can define two of them to be whatever you want, and then you have one equation and one unknown.

Because this works for literally any a and b you choose you stupid fucking nigger desu

use those mile long equations then, you literal faggot.

you must be in the 5% that can't solve it

Git gud.

dailyfeynmanlongdivisionpuzzles.blogspot.com/?m=1

>doesn't say what apple is

That's what I said, but it is the only possible solution.

As in, if you simplify all of that to get rid of the fractions and then get a polynomial in 3 variables, the only integer root is 0,0,0. But then that doesn't work for the original system that involves fractions.

The implication that 95% of people can solve this means it has a low value integer solution. Which is false. A puzzle that begins with a false statement is not worth solving.

>11 is too big of a number for me

4=fruit salad

This is right

Apple = Banana = Pineapple = -1/12