Why is zero raised to zero undefined but every other number raised to zero equals 1?

why is zero raised to zero undefined but every other number raised to zero equals 1?

Who comes up with this shit and why do we listen to them?

pepe

lim a,b ---> 0 a^b = ??????

When working with integers, 0^0 = 1, but when you extend the definition of exponentiation to real numbers the equality doesn't hold anymore because x^y is not continuous in (0, 0)

I don't understand what you're trying to communicate to me friend.

I'm currently working on getting 100% on algebra on khan academy.

Okay, since you haven't had calculus let me put it this way

why is zero raised to zero undefined but zero raised to any other number is zero?

why is zero raised to zero undefined but every other number raised to zero equals 1?


These arguments both use the same logic, but they give contradictory results. Please try again

[math]0^0 = 1 [/math], by definition. i'm not sure what you're asking

Khan has a video on this.

0^3 = 0*0*0
0^2 = 0*0
0^1 = 0
0^0 = 0/0 = undefined.
The whole thing with 0th power isn't just a definition - it means that the number is divided by itself. You can't divide by zero, so naturally you can't raise 0 to the 0th power.

That definition is hardly widely agreed upon.