3/3 = 3+1/3+1 = 1

3/3 = 3+1/3+1 = 1
2/2 = 2+1/2+1 = 1
1/1= 1+1/1+1 = 1
0/0 = 0+1/0+1 = 1


Why is this wrong?

why does 0/0 need to have a value?

a value of 0 in the denominator is always undefined so impossible.

-1/-1 = ????

0 isn't a number

It doesn't need to have value, it just so happens that it does.

0/0 is considered indeterminate, you disgusting brainlet. This is because you could put a 1,2, pi, or any other value on the LHS. For example,
0/0 = x
0 = 0*x, which is true for all x.

Now fuck off and never post this bait again.

You cannot divide something or nothing by nothing.

No, it does not.

Pic related is OP

Explain this brainlet

Are you trying to imply that 0 = 1 = 2 = ... ?

shoddy programming

Domain restriction

0 = True False 1

0=0+1=1+1=2+1=3 ...

>There is no "zero"! Nothing is not a number!
>You can't do a-b if b>a! It makes no sense!
>Well, what you absolutely can't do is to take a square root of negative numbers! It just doesn't make SENSE!

>0/3 = 0
>0/2 = 0
>0/1 = 0
>0/0 = 1

>but it is TRUE, i tell you

wow ebin math :DDDD

0/0 = 1
2*(0/0) = 2
2 = 2*(0/0) = (2*0)/0 = 0/0 = 1

broof that 2 = 1
:----DD

Done

any number divided by 0 equals +-∞. That undefined, out-of-bounds bullshit is for precal noobs.

Yes it is you fucking retard. Go back to grade school math faggot.

>equals +-∞
Wrong.
These arent real numbers it makes no sense talking about "equal".

>visit sci for first time
>expecting everyone to be smart
>see this shit
Ya fuck this

Infinity has numerical properties and behaves like any number in many cases. So blow it out your ass.

Kys brainlet. 4/0=infinity? well then it should be infinity * 0=4 is it true? No. Jesus you're stupid. Go back to kindergarden.

3/3 = 3 + 1/3 + 1 = 1
3 + 1/3 + 1 = 1
3+1/3 = 0 ??

ignoring the division by 0 for a moment, am i missing something?

3+1/3+1 = 1 is wrong.

3/3=3+1/3+1=1+0/1+0=-0+1/0-1=-1*0+1

2/2=2+1/2+1=1+0/1+0=-0+1/01=-1*0+1

1/1=1+1/1+1=1+0/1+0=-0+1/0-1=-1*0+1

0/0=0*1/0*1=1*0+0*1=0

>3/3 = 3+1/3+1
What?

>i apply this rule of math and discard the other rule
>woa why is this wrong?!!

Reductio ad absurdum.

The rules of addition are not the rules of division, nor can division be derived from the rules of addition.

1=2 - true = true/2=2 true -1 false=false/true = true=0.5+1.5 false= 1 (((3/3)))=1 true +1=1-false=-0.5 false

3/3 = 9/3 + 1/3 + 3/3 (= 3 + 1/3 + 1)

What kind of math is this bullshit?
>not even correct
do your math right

Calling 0 a number is like calling "nothing" a feeling. You can say "I feel nothing" and you can say "I have 0 apples" but that doesn't mean that "nothing" is an feeling or that 0 is a number.
>Infinity has numerical properties and behaves like any number in many cases
Just like 0, which is also not a number.

>0/0 is considered indeterminate,
Please go find out what that term means before throwing it into conversations to which it is not in any way related.

3/3=1/1=1

3/3=1^3=1*1*1=1=3/3
3/3=(1/3)*3=3/3=1
3/3=3/1*1root9=3/(1/3)=3/(3/3)=3*1/1=3/3=1

Why didn't you try -1/-1 user?

Because x is strictly different than x+1, assuming x is any complex number
0/0=a*0/0 for all a with the same assumption.

0/3 = 0
0/2 = 0
0/1 = 0
0/0 = 0
Why is this wrong?

Why is this wrong?


Because you made a mistake on the last one.

0/0 = 1

>doesn't understand limits

what the heck

So I'm reading What's Mathematics and it basically says that all math past natural number operations is pure convention. How fair is that assessment?

> print("The number is false.")

0/3 = 0
0/2 = 0
0/1 = 0
0/0 = 0

Indeterminate forms really only apply when you are talking about lhopitals rule m8.

The real reason this doesn't work is because the ring of fractions with respect to a multiplicatively closed subset S is just the zero ring if 0 is in S.

>implying anything except 1 is not just convention

How many times can you take 0 away from 0 to get 0?

You can approach zero as a denominator, but you can never reach it because it's undefined.