Welp... this is the end bois

Welp... this is the end bois

You could literally construct a framework for which these are true

Brainlets GET OUT OUT OUT OUT OUT

these are all corollaries of the fact that for all functions f, we have f(x+y)=f(x)+f(y)

Lol! You sure told them... I mean me???

doesn't (a+b) ^2 = a^2 + 2ab + b^2?

What are you in middke school?

it equals a^2 + b^2 or a + b^2 depending on how you do your pemdas

Not in a ring of characteristic 2.

a and b are letters lmoa you can't add letters

a+a=b
a+b=c
b+b=d
etc etc
don't ask about the capitals