Which bit is wrong?

Which bit is wrong?

Can't simplify by 0

Going from the penultimate line to the final line.

2*0 = 0

Simplifying this to 2 = 1 requires dividing by zero, but division is not defined when the second input is zero.

Oh!
Thanks buddy,

hahahahahhaha

This thread was not worth bumping. The polite sage is still a thing.

Dude
2(a-b)=a-b
2=((a/b)^-1)(a-b).
is not 2=a-b/a-b
Go back to basic Algebra

Replace a and b with x and see how retarded it looks.

Op, what is a minus a? Is it 0? Yes?

Great. Kill yourself.

Even I explained it to you, you wouldn't understand. Brainlet

dividing by (a-b) is dividing by 0

The last line

That's irrelevant and only becomes relevant once values need to be plugged in. The definition of a derivative starts with division over a variable going to zero, but that doesn't prevent algebraic manipulation of the problem.

( Y o u )

Dunno if I'm being baited or not, but the values you plug in doesn't matter because

>a = b

no matter what value you plug in its still division by 0

>the general case doesn't matter

I actually tried to solve this for 5 minutes earlier this week and I just didn't get it, but now it's obvious.
Am I retarded?

It works, you just have to add some imaginary "dark numbers" to the right side so you can divide it properly.

All numbers are imaginary

this post is postmodern

what

>2(0)=0

>implying there exists a multiplicative inverse for (a-b) when a = b

This is so simple m8 a-b=0 and you cant devide by 0

a = b
a + a = a + b
a + a = a + a
2a = 2a
a = a

Brainlet who is bad at maths here

Why does a-b=0?

because a=b

Aaaaah

Thanks my dude, now I get it

b8

you assumed a = a in line 2.
so the result is not supprising

>When you go to the front page of Veeky Forums every now and then and this image is always there

I swear this is a running gag here