Which bit is wrong?
Which bit is wrong?
Can't simplify by 0
Going from the penultimate line to the final line.
2*0 = 0
Simplifying this to 2 = 1 requires dividing by zero, but division is not defined when the second input is zero.
Oh!
Thanks buddy,
hahahahahhaha
This thread was not worth bumping. The polite sage is still a thing.
Dude
2(a-b)=a-b
2=((a/b)^-1)(a-b).
is not 2=a-b/a-b
Go back to basic Algebra
Replace a and b with x and see how retarded it looks.
Op, what is a minus a? Is it 0? Yes?
Great. Kill yourself.
Even I explained it to you, you wouldn't understand. Brainlet
dividing by (a-b) is dividing by 0
The last line
That's irrelevant and only becomes relevant once values need to be plugged in. The definition of a derivative starts with division over a variable going to zero, but that doesn't prevent algebraic manipulation of the problem.
( Y o u )
Dunno if I'm being baited or not, but the values you plug in doesn't matter because
>a = b
no matter what value you plug in its still division by 0
>the general case doesn't matter
I actually tried to solve this for 5 minutes earlier this week and I just didn't get it, but now it's obvious.
Am I retarded?
It works, you just have to add some imaginary "dark numbers" to the right side so you can divide it properly.
All numbers are imaginary
this post is postmodern
what
>2(0)=0
>implying there exists a multiplicative inverse for (a-b) when a = b
This is so simple m8 a-b=0 and you cant devide by 0
a = b
a + a = a + b
a + a = a + a
2a = 2a
a = a
Brainlet who is bad at maths here
Why does a-b=0?
because a=b
Aaaaah
Thanks my dude, now I get it
b8
you assumed a = a in line 2.
so the result is not supprising
>When you go to the front page of Veeky Forums every now and then and this image is always there
I swear this is a running gag here