lim n -> inf
n/n =1/n+1/n+1/n+1/n+...
lim n -> inf, 1/n=0
n/n=0
tell me why
Why the "limit" is bullshit
Adam Wood
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Parker Bell
If you don't make the effort to format your post correctly with latex, then I wont make the effort to respond to it seriously
Xavier Taylor
Why does this need latex? just read
Michael Flores
The series converges at 0 because the function 1/n+1/n... where n goes to infinity represents a series of infinitesimally small quotients.
I know this is not a rigorous explanation but that's how I was taught to understand it
John Murphy
No. Do it right.
Luis Taylor
I don't understand your question at all.
Carter Price
how can you dont understand it?
Ian Roberts
>tell me why
you selectively choose some of the n's in the expression to take the limit at infinity for, then do some bullshit operations, then take the limit again for the same variable, this time taking it for the other n's in the expression
not sure why you think this is okay
Josiah Ramirez
>n/n =1/n+1/n+1/n+1/n+...
?
Chase Cook
what's wrong??
Jayden Bennett
[math]\frac{n}{n}[/math] for "n" going to infinity, the expression is in indeterminate form. So there's some errors in your notation. However, I understand what you're trying to ask
This explanation is the best so far, I suggest you read up on the properties of convergent series, then it'll be somewhat obvious why the answer is zero. Proving this is another story, but it's kinda unnecessary.
Eli Smith
then
lim n->inf, 1/n=0
n/n=(1/n)*n
what is it?
Josiah Peterson
Zero times infinity equals ???
Ryder Clark
what?
Nicholas Thompson
The limit of one over n as n approaches infinity equals one over infinity which equals zero.
The limit of n as n approaches infinity is infinity.
Consequently, the limit of one over n as n approaches infinity times the limit of n as n approaches infinity equals zero times infinity, which is undefined.
In other words, zero times infinity equals ???
Christian Rodriguez
1, by L'hopital's rule
Justin Stewart
Hunter Robinson
>1/n+1/n+1/n+1/n+...
what does this mean OP?
Eli Kelly
(1/n)*n
Jaxson Long
LaTex or die niggas
[math] \displaystyle{\lim_{n \rightarrow \infinity} \frac{1}{10^n} = 0} [/math]
Thomas Butler
seems right graphically
Joseph Adams
>tell me why
Why what?
You are taking the limit of n*(1/n) and are arguing that it goes to 0.
This batshit insane and if you have the slightest knowledge about calculus you should understand that just because 1 term in a series goes to 0 the whole series doesn't need to go to 0.
Tyler Rogers
>n/n=0
No.
Lrn2arithmetic
Cooper Wood
...
Easton Lewis
In general [math]\lim_{n\to\infty} a_n + b_n = \lim_{n\to\infty}a_n + \lim_{n\to\infty}b_n[/math] holds for a fixed finite number (here two) of summands (if the limits exist).