we have irrefutable, measurable, repeatable, mathematical, proof that the Earth is flat. That is true science. We don’t not have to speculate, theorize, or trust any government agency. And this visual, mathematical proof that the Earth is not a sphere means that every alleged picture or video from “space” of the Earth being a sphere has been fake. And then, when you begin to look at the so-called pictures from NASA and other space agencies with some scrutiny, you find that they have obvious signs of forgery.
Well here's some food for thought, why don't you go over the edge and jump?
Christian Reyes
Back to school please
Oliver Nguyen
Kys faggot
William Turner
I have a hammer
Come closer little grasshopper, let's debate
Aaron Gomez
Nasa lies doesn't mean the world is flat, you are making people who have critical thought about the moon landing and NASA achievements look like crazy tinfoil flat earthers that repeat this nonsense over and over asking for a beating.
John Roberts
Mods pls delet thred
Oliver Gutierrez
there is no edge. but whatever is beyond the icewall is of interest.
Carson Bennett
...
Aiden Hernandez
obviously its the entrance to hollow earth where the aliens and Nazis hang out and also there is inter dimensional portals there connecting to alternative planes of existence where spirit beings live. Plateaus are also tree stumps.
Brayden Gomez
I was going to let this thread 404, but since people can't just leave it alone...That equation for "curvature drop" (ie. the amount of an object hidden by the earth) only works if you're very close to the ground (or more accurately have 0 height). This actually makes that approximation very useless, so in general you should use: [eqn] h = \left [ \left ( L - \sqrt { 2RH - H^2 } \right )^2 + R^2 \right ] ^{ \frac { 1 } { 2 } } - R[/eqn]Where h is the "curvature drop", H is the hight of the observer, L is the distance to the object, and R is radius of the earth. We can re-write that as [eqn] h = R \left [ \left \{ \frac { ( L - \sqrt { 2RH - H^2 } )^2 } { R^2} +1 \right \}^{ \frac { 1 } { 2 } } -1 \right ] [/eqn] Which we can Taylor expand to get [eqn] h \approx \frac { ( L - \sqrt { 2RH + H^2 } ) } { 2R } [/eqn]Which in the limit [math] H \to 0 [/math] Gives [eqn] h = \frac { L^2 } { 2 R } [/eqn]Which on substituting L=1 and R = 4,000 gives [math] h = 1.25 \times 10^{-4} \approx 8" [/math], so over 1 mile, about 8 inches of an object would be hidden by the curvature of the earth, as expected.
I only mention this because I see a lot of the "flat earth" crowd using the end result, then getting erroneous results, but not understanding why.
Robert King
>knifes don't cut under water What the actually fuck?
Mason Lewis
>That equation for "curvature drop" (ie. the amount of an object hidden by the earth) only works if you're very close to the ground (or more accurately have 0 height).
The formula for calculating curvature is very simple geometry. It works above and well below sea "level"
your formula is the definition of moving the goalpost...and the least you could do is post a picture of the earths curvature to verify the accuracy of your frmula.
but you cannot, as there is no curve.
Eli Myers
wait, if the earth is "flat", how can you travel around the world (and end back on your starting point)? what excuse do they have for this?
Jaxon Diaz
yeah because your shitty photo really shows the minute curvature of the earth in the distance. fuck off.
Brayden Foster
I actually have alot of photos.. so get your theories and ad hominems ready.
Carson Phillips
>It works above and well below sea "level" But it doesn't, for one it's clearly going to be a function of the height of an observer. Moreover consider if you were 8" above the earth, then you'd see the "hidden" bit of the object. In fact using full equation (and some approximate values) you get the "curvature drop" to be about 0.8".
Dylan Hall
Using your mathematically proven flat earth model, can you go ahead and tell me when the next total solar eclipse is? And where on earth I'll need to stand to see totality and for how long totality will last at that location?
Cuz at least the fake round earth model can do that
Blake Brown
They think you are actually walking in a big circle. Unless of course you walk across the south pole, then they think you just didn't and lied about it
Lucas Lee
looping east and west
Ryder Miller
August 21st
The Newtonian hypotheses involves the necessity of the Sun, in the case of a lunar eclipse, being on the opposite side of a globular earth, to cast its shadow on the Moon: but, since eclipses of the Moon have taken place with both the Sun and the Moon above the horizon, it follows that it cannot be the shadow of the Earth that eclipses the Moon; that the theory is a blunder; and that it is nothing less than a proof that the Earth is not a globe.
but tb honest eclipses have been accurately predicted by mayans and chinese who hols fast to the flat geocentric model.
only jesuit astronomy alters this.
Caleb Garcia
Radius to the north pole is actually 3949.9 miles, and the radius to the equator is actually 3963.2 miles.
Jeremiah Ortiz
...
Chase Lopez
>Newtonian And this difference is yet to be observed or measured, furthermore nasa and government space authorities admit the use of cgi and compositing images of Earth, finally the earth appears and is measured as a perfect sphere rather than an oblate spheroid which would drastically alter the moon earth sun eclipse hypothesis.
Ryder Morales
HERES AN IDEA IF PEOPLE STOPPED ADDRESSING THEIR POSTS SERIOUSLY, PEOPLE WOULD STOP POSTING
So post about whatever you want on these threads, except correcting flat earth bullshit.
Dominic Thompson
The Flat Earth Meme is pushed by shill to strengthen PopSci, NASA authority. When you deny their authority you will be put together on the same bag
