How is this type of expression supposed to be evaluated? Is it the negative number 3 to the 2nd power, or the negative of 3 to the 2nd power?
9 or -9?
PEMDAS doesn't involve this as in this expression '-' is a unary operator, not subtraction operator
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(-3)^2=(-3)(-3)=9
-3^2=-(3)(3)=-9
I am aware there are two ways to interpret this, hence why I'm asking the question. I asked which way is the correct way.
the one you wrote is the second one i wrote, so -9
It's 9 how do you not know this? If it were -9 then the square root of -9 would be -3 and we wouldn't have imaginary numbers
it's -9. Any calculator you ever put this on will tell you that because PEMDAS does tell you how to do this. Any negative can be thought of as the number multiplied by -1, so what you have would be (-1)3^2.
there is only 1 way to interpret it. Take a math class or read a book.
Its -9 because of BODMAS.
3^2 takes priority, that's 9, then its -1*9 = -9.
This is how you get inverted parabolas, through F(x) = -(x)^2
If you want 9 then the negative has to be included with the brackets.
nigger you didn't even read the post you replied to.
-3^2 = -(3^2) = -9
To get 9 you would have to write:
(-3)^2 = (-3)^2 = 9
To better understand, think of any negative number as a positive number times -1. So:
-3^2 = -1*3^2 = -9 by exponent first then multiplication
(-3)^2 = (-1*3)^2 = 9 by parentheses first then exponent