99% of Veeky Forums is too stupid to solve this

99% of Veeky Forums is too stupid to solve this.

Prove me wrong, brainlets.

Other urls found in this thread:

en.wikipedia.org/wiki/Chinese_remainder_theorem
quora.com/How-do-you-find-the-integer-solutions-to-frac-x-y z- -frac-y-z x- -frac-z-x y-4
twitter.com/SFWRedditImages

1 2 3 4

I will post the answer after enough people try.

So the answers can't be decimals?

No.

Not possible unless one of them is 0

I never waste my precious brainpower on stupid fruit problems

a=154476802108746166441951315019919837485664325669565431700026634898253202035277999
b=36875131794129999827197811565225474825492979968971970996283137471637224634055579
c=4373612677928697257861252602371390152816537558161613618621437993378423467772036

THE ANSWER IS MANGO GOYIM

...

en.wikipedia.org/wiki/Chinese_remainder_theorem

Solve it then, you can't with just Chinese Remainder Theorem

You can narrow it down.
Just doing mod 2, you cant have exactly 2 evens.

so the number of solutions is down from infinite, to 1/3 of infinite

Ive never seen a proof of the answer, can someone post it when they decide theres been enough replies?

3/4 of infinite, but you tried.

its actually 1/2 if we want to be pedantic.

this, 2/17>0.01, /proof /thread

quora.com/How-do-you-find-the-integer-solutions-to-frac-x-y z- -frac-y-z x- -frac-z-x y-4

7

> elliptic curve

Assume x(x+y)*3.3
Smaller fractions will be less than 1/7.6 and 1/3.3
z>(x+y)*3.565
keep going...

z>(x+y)*3.6 ish

I'm trying to use infinite descent.
x

11, 9, -5

Apple worth 4, pineapple and banana 0

>4 / 0 + 0 is impossible so it remains 4
> other 2 are 0 divided by 4 which is still 0

Dipshits. God math is easy

why is Veeky Forums just filled with people trying to prove how smart they are?