Well?

You are literally this retared

I thought that
[eqn] \frac{1}{6} + \left( - \frac{1}{3} \right) = -\frac{1}{6} \\
\frac{1}{6} - \left( - \frac{1}{3} \right) = \frac{1}{2} [/eqn]

>can't use tex
>calls others retarded

do half an infinity sign in tex then retard

[math]\propto[/math]

>half an hour to do a 3/4 instead of 1/2
lol

solving actually gives A=\frac{1}{12} and B=-\frac{1}{6}

isn't that just alpha?

[math]\alpha[/math]

x

The other half is left as an exercise to the reader.

first one is odder