Math geniuses of Veeky Forums

can you solve this?

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wolframalpha.com/input/?i=sum&rawformassumption={"F", "Sum", "sumfunction"} ->"(1/(2^x))*(x-1)"&rawformassumption={"F", "Sum", "sumvariable"} ->"x"&rawformassumption={"F", "Sum", "sumlowerlimit"} ->"1"&rawformassumption={"F", "Sum", "sumupperlimit2"} ->"infinity"&rawformassumption={"C", "sum"} -> {"Calculator"}.
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This is actually a good one.

Gott würfelt nicht.

Pretty sure it would converge to extinction.

Wouldn't be the expected ratio 1:1 and the expected value of children per household 2? Correct me if I'm wrong

Assuming everybody always marry and have children, always try to have as many kids as possible and only marry once, there will be always the same number of parents. If there are a hundred thousand parents in the first generation, there will be a hundred thousand in the second, and so on. So the ratio will always be constant. That's the beginning of the solution.

>male children
what an abomination

Wow, what an original riddle you got there. Did you come up with it all by yourself? I bet no-one has ever seen that before. No-one, ever.

Dr Sage & Mr Hide

All couples will have a male, so 1.
Half will have a female, so 1/2. But a quarter will also have one more girl, 1/4. An octave will have one more, and so on. We have the infinite sum 1/2+1/4+1/8... Which results in 1.
So we will have the same number of boys and girls. Feminists got mathed.

I think this is the right answer