Negative light speed

According to the equation e = m*c^2, if you equal it to c, there is a negative c as a solution.
If math doesn´t lie, then is physics wrong?

Wowee, we got a brainlet here who only looks at the popular culture representation of physics lads!

But no, the equation e = mc^2 is actually incomplete; Einstein's entire formula is e^2 = m^2c^4 + p^2c^2

p represents a particles momentum; for normal matter, this is just m*v, but it isn't represented like that here because Einstein developed a way to quantify a photon's momentum even though it has no mass.

As a last thought; c is the speed of light. A negative speed, in almost all circumstances, merely represents a specific direction; if you have no direction, you can reorient your reference and redefine -c = c for simplicity in your math.

You're incorrect about everything you said

Wouldn't that just mean light going in the opposite direction?

No, a negative speed is simply a speed that goes to the opposite direction of the one you considered positive, it simply means going backwards.
For example, if you consider downwards positive, a rock falling has positive values for its speed and a balloon rising has negative values for its speed

Congrats, user, you made me lose my shit

you mean like how in particle annihilation you get two particles going in
O P P O S I T E
D I R E C T I O N S ? ? ?

*photons
fugg

>c isn't the speed of light
> e^2 =/= m^2c^4 + p^2c^2

Sqrt (x^2) = |x| by definition.
The square root of a positive number is always positive.

do you want to know how stupid you are given you just laughed at something which is entirely true

AHAHHAHA ITS THE OPPOSITE DIRECTION HAHAHAHAHAHAHH

>Negative speed
>Opposite direction

Depends on your rules.

(-5)^2 = 5^2 = 25 in normal high school math. That means every number has two square roots.

Idgi

Photons are particles you dipshit.

The "negative c" doesn't exist. In the equation "[eqn]E = mc^2[/eqn]" c only acts as a constant, it isn't a variable that you can solve for and then manipulate. You end up getting the absolute value of c equal to the square root of E/m. c is positive so it's absolute value is still c. E is positive because you can't have negative energy. m is positive because you can't have negative mass.

the speed of light really just means the velocity of light and the velocity can be negative depending on the reference point

How fast are you right now? I'm like, minus 7

Two things:
Just because there are multiple solutions, physics requires that at least one of those solutions exist.
Secondly... Negative speed is just turning around.

Enjoy your free (You)s

no it doesn't
square root is a *function*, by definition it has only one answer
[math]
\sqrt {x^2} \ne \pm x, \quad \sqrt {x^2} = \left | x \right |
[/math]

Yes... Where x is +/-
You aren't solving for x in your second question.
You aren't wrong, just incomplete

Speed is always positive

speed (how fast u r) is not a vectorial magnitude so it can't be negative u fuckin brainlet

I'm not giving him any so I will use you as a proxy to attack him viciously.

Let's just go back to basic "here's how you do basic mathematics" shall we?

Asking "what's 21 divided by 7?" is asking "what number, when multiplied by 7, equals 21?"

Taking the square root of x is asking "what number, when multiplied by itself, equals x?"

In normal, everyday mathematics, [math]y=\sqrt{x}[/math] has two solutions for y: [math]y=-|\sqrt{x}|[/math] and [math]y=+|\sqrt{x}|[/math].

>Einstein's entire formula is e^2 = m^2c^4 + p^2c^2
this implies complex valued light velocity as well you retard.

c is a constant you fucking retard

>c is a constant
hello brainlet

That's different though. The solution to the equation x^2 = 25 is +- 5. That is not equivalent to saying that sqrt (25) = +-5. This isn't a debate. The square root by definition is positive. You've just been taught wrong by brainlets.

wrong
right

brainlet who read a wikipedia article here
wouldn't this have something to do with imaginary time?

>-c = c
>2c = 0
>c = 0

No, he's just saying that if you treat a constant as a variable, then you get an imaginary number. It has no basis in reality.

>Not working in natural units
Then it's just [math] E = m [/math]

Inverse operations aren't always perfect opposites. Just look at indefinite integrals and their "plus C" term.

>y=x√ has two solutions

that's an equation, not a function

-c would never equal c on the same axes though?
-c is equivalent to c in the sense that we can just rotate the axes, OP did leave it unclear though

pls explain

[math]y^2 = x[/math] has two solutions, [math]\pm\sqrt{x}[/math] but [math]\sqrt{x}[/math] is defined to be the principal (positive) root.

c is a constant (doesn't have a direction) like a vector would.

would love an explanation of which direction a ratio moves in.

>hello brainlet
t. Brainlet

that's because you can only walk forward with lightspeed.
since you are slower when you walk backwards you can never reach negative lightspeed.
some people are pretty good at running backwards, but they are still slower than forward runners