Hi guys, feeling a bit lost on a mechanical physics problem.
A particle undergoes simple harmonic motion (oscillation) with a frequency of 10hz. Find the displacement (or position) x as a function of time given the following information: x(0) = 0.25m and x 0 (0) = v 0 =0.1m/s.
What I have so far:
x(t) = .25cos(10t) + 0.1/10 sin (10t)
Am I on the right track? Or should I use
d^2x/dt^2 = -k/mx
P-p-pls respond
>Or should I use
>d^2x/dt^2 = -k/mx
Are you still in high school or retarded...
d^2x/dt^2 = -k/mx with boundary conditions gives x(t) = .25cos(10t) + 0.1/10 sin (10t)
Jeez man, physics obviously is not my forte, was forced to take this class. And my professor barely teaches us anything.
Anyways, mind pointing me in the right direction?, also in the problem I made a typo, it is X'(0) = vₒ = 0.1m/s
dual n back exercises
so d^2x/dt^2 = -k/mx is a differential equation that has the solution
x(t) = A cos(Bt) + C sin(Dt)
the frequency is 10hz, so B = D = 2pi/10 (or maybe 2pi*10 idk)
x(0) = A cos(0) + C sin(0) = A = 0.25m
this fixes A
x'(0) = -AB sin(0) + CD cos(0) = CD = 0.1
this fixes C
>I'm asking for the steady state solution.
>Ut=0
This is wrong. Steady state solution is when t->inf. You already had enough equations to solve the differential equation in the 4 lines before it. You solve it, apply the boundary conditions, then apply the limit.
This helped so much. Thanks.
The problem:
I need a way to calculate the coordinates (latitude/longitude) from the center point within the green circle.
What I have:
-> A pre processed segmented satellite image compressed in a jpg file.
-> The lat/lon from the center of the image
-> The distance in pixels from the center of the image to the center of the circle
PS: no geo data attached to the image :(
What the FUCK is a tensor and why is there no explanation that doesn't take a fucking page to write or is just "lol it transforms like this, don't worry about what it is xD"
